X= 70 degrees
Y= 70 degrees
Understand that every triangle has three angles and they add up to 180 degrees.
If I split this triangle in half the total degrees of each individual piece will be 90 degrees. A split in the isosceles triangle will also cause the 40 degrees to halved (thus, how I got 20 degrees in our 90 triangle).
Since we are dealing with an isosceles triangles two of the sides will be equal (hence, the dashes on the triangles sides). Therefore, x and y will also be equal.
Now if our 40 degreed angle is now 20 degrees, we have an unknown angle and the triangle in total now adds up to 90 degrees we can set up an equation.
20 + y = 90
Y = 70
Since X and Y are equal, X will also be 70.
If we return to to the isosceles triangle before it was split (use your photo for reference) and we add 40 +70 + 70 we will get 180 degrees. Which is the standard total of degrees for any triangle that is not a 90 degreed triangle.
I hope this helps. Feel free to ask questions.
Below I uploaded my work.
Answer:
(4,3)
Step-by-step explanation:
Answer:
x = lillies
y = tulips
x + y = 13
1.25x + .90y = 14.85
-1.25x - 1.25y = -16.25
1.25x + .90y = 14.85
-0.35y = -1.40
y = 4 tulips
x + 4 = 13
x = 9 lillies
(9 lillies, 4 tulips)
Step-by-step explanation:
Answer:
Claim 2
Step-by-step explanation:
The Inscribed Angle Theorem* tells you ...
... ∠RPQ = 1/2·∠ROQ
The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.
... 2·∠RPQ = ∠ROQ
The symmetric property of equality says you can rearrange this to ...
... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ
_____
* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.
You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.