Answer:
0.2-0.05=0.15
Step-by-step explanation:
0.2=0.20
0.20-0.05=0.15
Answer:
y = 5x + 2 . . . . . . . . . . (1)
3x = -y + 10 . . . . . . . . (2)
3x = -(5x + 2) + 10
3x = -5x - 2 + 10
3x + 5x = -2 + 10
8x = 8
x = 1
y = 5(1) + 2 = 5 + 2 = 7
Solution is (1, 7) The answer is (1,7)
Step-by-step explanation:
Answer:
The average velocity of the ball at the given time interval is -122.3 ft/s
Step-by-step explanation:
Given;
velocity of the ball, v = 34 ft/s
height of the ball, y = 34t - 26t²
initial time, t₀ = 3 seconds
final time, t = 3 + 0.01 = 3.01 seconds
At t = 3 s
y(3) = 34(3) - 26(3)² = -132
The average velocity of the ball in ft/s is given as;

Therefore, the average velocity of the ball at the given time interval is -122.3 ft/s
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Answer:
C and D
Step-by-step explanation:
Mathematically, a unit circle is one in which the value of the radius is 1 unit
Generally, for a unit circle we have it that;
r^2 = x^2 + y^2
where (x,y) represents the coordinates of a point on the unit circle
But from above, r = 1
Thus:
x^2 + y^2 = 1
Looking at option C, by squaring each coordinate, we have
(6/7)^2 = 36/49 and the second as 13/49
by adding both, we have
36/49 + 13/49 = 49/49 = 1
Thus, we have this as a coordinate on the unit circle
For the last option;
(5/13)^2 = 25/169 and (12/13)^2 = 144/169
Adding both, we have;
25/169 + 144/169 = 169/169 = 1
So this is also a point on the unit circle