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tiny-mole [99]
4 years ago
12

Below are the scores for players competing in a two-day golf tournament. Which golfer had the greatest difference between his or

her day 1 and day 2
scores?
Day 1 Score
Day 2 Score
-2
Player
Janelle
Ken
Dave
Kim
+1
0
-1
+ III​
Mathematics
1 answer:
creativ13 [48]4 years ago
3 0

Answer:

<u>The correct answer is D. Kim +III</u>

Step-by-step explanation:

1. Let's review the information given to answer the question correctly:

Number of days of the golf tournament = 2

Players competing in the tournament = {Janelle, Ken, Dave, Kim}

Differences between 1st and 2nd day scores = ( +1 , 0, - 1, + III)

2. Let's find out which golfer had the greatest difference between his or her day 1 and day 2  scores.

After reviewing all the differences, we find that Kim has the greatest difference (+ III or + 3). III is the expression in roman system to write 3.

<u>The correct answer is D. Kim +III</u>

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Lena reflected this figure across the x-axis. She writes the vertices of the image as A'(−2, 8), B'(−5, 6), C'(−8, 8), D'(−4, 2)
garik1379 [7]

Answer:

Option A) she reflected the pre-image across the y-axis

Step-by-step explanation:

we know that

When reflect a point across the the x-axis the rule of the reflection is equal to

(x,y) -----> (x,-y)

When reflect a point across the the y-axis the rule of the reflection is equal to

(x,y) -----> (-x,y)

In this problem we have

A(2,8),B(5,6),C(8,8),D(4,2)

Applying the rule of the reflection across the x-axis

The coordinates of the image would be

A'(2,-8),B'(5,-6),C'(8,-8),D'(4,-2)

Applying the rule of the reflection across the y-axis

The coordinates of the image would be

A'(-2,8),B'(-5,6),C'(-8,8),D'(-4,2)

therefore

she reflected the pre-image across the y-axis.

8 0
4 years ago
The school ski club went on a ski trip. The ski changed the group $1120 for 32 lift tickets. How much was each ticket?​
katen-ka-za [31]

Answer:

$35 per ticket

Step-by-step explanation:

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3 0
3 years ago
For a circle with a diameter of 6 meters, what is the measurement of a central angle (in degrees) subtended by an arc with a len
Sholpan [36]

Answer:

\boxed{\boxed{\theta=150^{\circ}}}

Step-by-step explanation:

We know that,

\text{Arc length}=r\cdot \theta

where,

r = radius,

θ = central angle in radian.

Given,

diameter = 6 m, so radius = 3 m.

\text{Arc length}=\dfrac{5}{2}\pi

Putting the values,

\Rightarrow \dfrac{5}{2}\pi=3\theta

\Rightarrow \theta=\dfrac{5}{2\times 3}\pi

\Rightarrow \theta=\dfrac{5}{6}\pi=\dfrac{5}{6}\times 180^{\circ}=150^{\circ}


3 0
3 years ago
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Vlada [557]
A. 300-200=100
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