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rodikova [14]
3 years ago
6

Find the value of x in the triangle. Please show work. Help

Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0

there is no triangle drawn

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What is the ratio of a:b, knowing that a-b/a+b = 3/5.
ser-zykov [4K]

Answer:

4:1

Step-by-step explanation:

\frac{a-b}{a+b} = \frac{3}{5}

4-1 = 3

4+1 = 5

5 0
3 years ago
Choose the fragment that best completes the following sentence. Interest charges will not be applied to a credit card when-
aliya0001 [1]

Answer:

A.) the balance is payed off during the grace period  

Step-by-step explanation:

Paying only the minimum payment would cause the remainder of the balance to draw interest charges, whether paid during the grace period or before the due date.

Paying off the balance during the next billing cycle will still result in interest charges for the current billing cycle.

Paying off the balance during the grace period, however, will not result in interest charges.

4 0
3 years ago
Read 2 more answers
12. On a table there were 16 dimes and quarters. The value of the coins was
7nadin3 [17]
6 quarters and 10 dimes
6 0
3 years ago
1. Complete the tables of values below for graphing the secant and cotangent functions. You can type “U” for an undefined value.
Katyanochek1 [597]

Step-by-step explanation:

1. All the trigonometric values can be found using the unit circle.  See attached table.

2. Graph:

desmos.com/calculator/10n7yrm3tm

3. All trig functions are periodic functions.  The period of secant and cosecant is 2π.  The period of cotangent is π.

4. Using the table from step 1 and the graph from step 2, secant has a domain of x ≠ pi/2, 3pi/2 and a range of x ≤ -1, x ≥ 1.  Cotangent has a domain of x ≠ 0, pi, 2pi and a range of -∞ < x < ∞.

5. Graph:

desmos.com/calculator/tldiqt7qra

Cosecant has the same graph as secant shifted π/2 to the right.  So they have different domains, but the same range.

6 0
3 years ago
What is an equation of the line that passes through the points (6,−4) and (−6,2)? Put your answer in fully reduced form
katovenus [111]
Y=mx+b
m=slope
b=yintercept
slope=(y1-y2)/(x1-x2)
(x,y)
x1=6
y1=-4
x2=-6
y2=2

(-4-2)/(6-(-6))=-6/12=-1/2
y=-1/2x+b
subsitute one point
(6,-4)
x=6
y=-4
-4=1/2(6)+b
-4=3+b
subtract 3
-7=b
y=-1/2x-7 is answer

6 0
4 years ago
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