I need to find the side lengths. Plz help

Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili

lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

B = bugs are present in a computer program.

D = a de-bugging program detects the bug.

The information provided is:

$P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02$

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event E given that another event X has already occurred is:

$P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}$

Use the Bayes' theorem to compute the value of P (B | D) as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333$

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

$=0.3333\times 0.3333\\=0.11108889\\\approx 0.1111$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

$=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0

3 years ago

BRAINLY!!!- if a=7, b=8, and c=9.2 is this a right triangle? why?

Travka [436]

Answer:

no

Step-by-step explanation:

If this were a right triangle we would assume the Pythagorean Theorem to prove it

$a^{2} +b^{2} =c^{2}$

$7^{2} +8^{2} =9.2^{2}$

this gives us

49+64=84.64

this is 143=84.64 and therefore not equal and not a right triangle

7 0

3 years ago

ANSWER ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

aev [14]

Answer:

Sequence 1: Translate 5 units to the right, and 5 units down

Sequence 2: Reflect across the origin, translate 1 unit down, 1 unit to the right

Step-by-step explanation:

Chose 1 point to focus in, such as (-1, 1)

Move that point 5 units to the right, and 5 units down. See how it matches up with the same corner of the red square?

Now, use that same point, and change the signs of both the x and y, this is to reflect across the origin. (In reality, you are just reflecting across the x and y axis)

So you originally have: (-1,1) -> (1, -1)

Now move this point one unit to the right, and 1 unit to the left.

It may seem that you made it touch the wring corner, but do the same thing with another corner's points. They all flipped!

8 0

3 years ago

In \triangle KLM,△KLM, \overline{KL}\cong \overline{MK} KL ≅ MK and \text{m}\angle M = 43^{\circ}.m∠M=43 ∘ . Find \text{m}\angle

svetoff [14.1K]

Based on the definition of an isosceles triangle, the measure of angle L is: 43°

Recall:

An isosceles triangle has two side lengths that are equal in size, and also the angles opposite the equal sides are congruent.

Given that KL ≅ MK in △KLM, it means △KLM is an isosceles triangle.

If m∠M = 43°, therefore, m∠M = m∠L (equal angles directly opposite KL and MK).

This implies that: m∠L = 43°

In summary, based on the definition of an isosceles triangle, the measure of angle L is: 43°

Learn more about isosceles triangle on:

brainly.com/question/11884412

6 0

3 years ago

200z + 50 = 8000 solve this problem

kramer

Answer:

39.75

Step-by-step explanation:

First, subtract 50 from both sides

200z + 50 - 50 = 8000 - 50

200z = 7950

Then isolate the variable by dividing both sides by 200

200z/200 = 7950/200

z=39.75

8 0

3 years ago