Ask question

Ask question

All categories

3 years ago

13

What steps would you take to compare 2 kilograms and 3,200 grams m

2 answers:

Bond [772]3 years ago

8 0

The step I will take is division

umka2103 [35]3 years ago

8 0

Use division bruv. It is what is probably the best.

You might be interested in

Please explain how to find the answer

irina1246 [14]

Answer:

$\rm x=\frac{46}{3}$

$\rm y=-\frac{25}{24}$

Step-by-step explanation:

$\huge\begin{array} {|c|} \hline\left. \begin{cases} { \rm\frac{ 1 }{ 4 } x+ \frac{ 4 }{ 5 } y = 3 } \\ { \rm\frac{ 5 }{ 16 } x- \frac{ 1 }{ 5 } y=5 } \end{cases} \right. \\ \hline \end{array}$

$\\ \Large \overline{ \rm - \: Steps \: using \: substitution \: - }$

$\rm \frac{1}{4}x+\frac{4}{5}y=3$

$\rm \frac{1}{4}x=-\frac{4}{5}y+3$

$\rm x=4\left(-\frac{4}{5}y+3\right)$

$\rm x=-\frac{16}{5}y+12$

┈

$\rm \frac{5}{16}\left(-\frac{16}{5}y+12\right)-\frac{1}{5}y=5$

$\rm -y+\frac{15}{4}-\frac{1}{5}y=5$

$\rm -\frac{6}{5}y+\frac{15}{4}=5$

$\rm -\frac{6}{5}y=\frac{5}{4}$

$\bold{ y=-\frac{25}{24}}$

┈

$\rm x=-\frac{16}{5}\left(-\frac{25}{24}\right)+12$

$\rm x=\frac{10}{3}+12$

$\bold{ x=\frac{46}{3}}$

7 0

3 years ago

Read 2 more answers

Explaining a Rule for Dividing Fractions

Harlamova29_29 [7]

Answer:

One rule for dividing fractions is the rule where instead of doing 13/43, you can do 13 times 1/43.

Step-by-step explanation:

Yeah

5 0

3 years ago

Read 2 more answers

The _____ appears in the equation of a line as the coefficient of the variable x.

zvonat [6]

In the question <span>The _____ appears in the equation of a line as the coefficient of the variable x. it is.(slope)</span>

5 0

3 years ago

Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. a. Find the exponential model that represents the da

andreyandreev [35.5K]

Answer

I do not know

Step-by-step explanation:

6 0

3 years ago

Which equations represent the asymptotes of the hyperbola (x-1)^2/36-(y-2)^2/64=1 ?

allochka39001 [22]

Answer:

$4x+3y=10$ and $4x-3y=-2$

Step-by-step explanation:

The asymptote equation of a translate hyperbola with equation $\frac{(x-h)^2}{b^2}-\frac{(y-k)^2}{a^2}=1$ is $y=\pm\frac{b}{a}(x-h)+k$

The given hyperbola has equation: $\frac{(x-1)^2}{36}-\frac{(y-2)^2}{64}=1$

Or $\frac{(x-1)^2}{6^2}-\frac{(y-2)^2}{8^2}=1$

Comparing to $\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

We have a=6 and b=8, h=1 and k=2.

We substitute this values to get:

$y=\pm\frac{6}{8}(x-1)+2$

$y=\pm\frac{4}{3}(x-1)+2$

$3y=\pm4(x-1)+6$

We split the plus or minus sign to get:

$3y=4x-4+6$

$3y=4x+2$

$3y-4x=2$

Or

$3y=-4(x-1)+6$

$3y=-4x+4+6$

$3y+4x=10$

5 0

4 years ago