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monitta
3 years ago
7

What is the equation of the line shown in this graph?

Mathematics
2 answers:
Andrei [34K]3 years ago
8 0
Point slope or standard form? Standard is y=0-+1, point is y=1
Anna007 [38]3 years ago
6 0

Answer: y=1

Step-by-step explanation:

In the given picture , we have a line that is parallel to x-axis and passing through (2,1) and (-4,1).

The slope of the lien parallel to x-axis is 0 [∵ slope of x-axis is 0 and slope of two parallel lines are equal. ]

Equation of a line passing through two points (a,b) and has slope m is given by :-

(y-b)=m(x-a)

Put (a,b) = (2,1)  and m = 0 , we get

(y-1)=(0)(x-2)\\\\ y-1=0\\\\ y=1

Hence, the equation of the given line is : y=1

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3 years ago
Solve the simultaneous equations C^2+d^2=5 and 3c+4d=2
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And if you put that into the other equation
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c =  \frac{2 - 4 \frac{ \sqrt{15}  - 2}{ \sqrt{3}  - 4} }{3}







6 0
3 years ago
Read 2 more answers
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