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Mariulka [41]
3 years ago
13

9 A right rectangular prism What is the volume, in cubic meters, of the prism?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
6 0

Answer:

D. 203

Step-by-step explanation:

volume= width X height X length

volume= 8 X 7 1/4 X 3 1/2

volume= 203

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A right triangle has a base of 11 yards and a height of 7 yards . If you were to construct a similar but not congruent right tri
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Answer:

bae of 44 yds and a height of 28 yds

Step-by-step explanation:

11x7 = 88 yd^2 = area of small triangle

616/88 = 16 so the larger triangle area is 16 times larger than the smaller triangle.

The area of a triangle is not proportional to it's dimensions. An increase of 16 times the area only increases the dimensions by 4 times.

larger triangle dimensions are 11 x 4 = 44 and 7 x 4 = 28

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3 years ago
Plssssssssssssssssssssssss help
PIT_PIT [208]

Step-by-step explanation:

4x + 12° = 64° ( vertically opposite angle )

4x = 64° - 12°

4x = 52°

x = 52° / 4

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3 0
2 years ago
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the airline Middle School girls soccer team won 80% of the games this season if they won 12 games did they play
11Alexandr11 [23.1K]

Answer:

15 games

Step-by-step explanation:

80% of 15 is 12, it's as easy as that. Hope it helps!

4 0
3 years ago
If x and x+ 10 are a pair of adjacent angle find them ​
ikadub [295]

Answer:

85° and 95°

Step-by-step explanation:

Given that , x and x + 10 are a pair of angles .

  • If they will be pair of angles on the same line , then their sum will be 180° .

=> x + x + 10° = 180°

=> 2x = 180° -10°

=> 2x = 170°

=> x = 170°/2

=> x = 85° .

<h3><u>Hence </u><u>the </u><u>two </u><u>angles</u><u> </u><u>are </u><u>8</u><u>5</u><u>°</u><u> </u><u>and </u><u>9</u><u>5</u><u>°</u><u> </u><u>.</u></h3>
5 0
3 years ago
In which set(s) of numbers would you find in the number 733
Genrish500 [490]
<span>733 can be expressed as all from the option except option A)

So, the answer would be:
B) natural number 
C) whole number
D) irrational number
E) integer
F) real number

Hope this helps!</span>
5 0
3 years ago
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