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Inessa05 [86]
3 years ago
7

The sum of three consecutive even integers is 66. Which equation represents the scenario? x = 66

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0

Answer:

(D)

x + (x + 2) + (x + 4) = 66

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Which point is on the circle centered at the origin with a radius of 5 units? Distance formula: StartRoot (x 2 minus x 1) square
Sergeeva-Olga [200]

Answer:

Option A) (2,\sqrt{21})

Step-by-step explanation:

The following information is missing in the question:

A. (2,\sqrt{21})

B. (2,\sqrt{23})

C. (2, 1)

D. (2, 3)

We are given the following in the question:

A circle centered at origin and radius 5 units.

We have to find the equation of a point that lies on the circle.

Let (x,y) lie on the circle.

Distance formula:

d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Putting

(x_2,y_2) = (x,y)\\(x_1.y_1) = (0,0)\\d = 5

We get,

5 = \sqrt{(y-0)^2 + (x-0)^2}\\\sqrt{x^2+y^2}=5\\x^2+y^2 = 25

is the required equation of point on the circle centered at the origin with a radius of 5 units.

The point (2,\sqrt{21}) satisfies the given equation.

Verification:

(2)^2 + (\sqrt{21})^2\\=4 + 21\\=25

Thus, (2,\sqrt{21}) lies on the circle centered at the origin with a radius of 5 units.

7 0
4 years ago
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