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irina1246 [14]
4 years ago
9

What is the value of the expression 1/5 divided by 4

Mathematics
2 answers:
Ket [755]4 years ago
8 0

Whenever we divide by a fraction, we change division to multiplication & flip the fraction which is a divisor.

The rule

\frac{a}{b}/ \frac{c}{d}

= \frac{a}{b}.\frac{d}{c}

Here we need to divide 1/5 by 4

But 4 can also be written as 4/1

So we have

\frac{1}{5} /\frac{4}{1}

\frac{1}{5} . \frac{1}{4}

\frac{1}{20}

The value of the expression 1/5 divided by 4 is 1/20 or 0.05.

VMariaS [17]4 years ago
6 0
1/5 divided by 4 is either 0.05 or 1/20.

Hope this Helps.
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Find the projection of u = <–6, –7> onto v = <1, 1> a. <-13/2,-13/2> b. <39,91/2> c. <-13/1764,-13/17
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<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

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The answer to the question

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