Answer:
Step-by-step explanation:
f * g = (x^2 + 3x - 4) (x+4)
open bracket
x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)
x³ +3x²-4x+x²+12x-16
x³+3x²+x²-4x+12x-16
x³+4x²+8x-16 (domain is all real numbers.
f/g = (x^2 + 3x - 4)/(x+4)
factorising (x^2 + 3x - 4)
x²+4x-x_4
x(x+4) -1 (x+4)
(x+4)(x-1)
f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)
Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.
Hence I got x - 1, and x cannot equal -4
So the domain is just all real numbers without -4
Answer:
x=2(twice)
y=0(twice)
Step-by-step explanation:
This question can be solved using substitution method
So let's solve
y=x+2....(1)
y=x2+5x+6....(2)
Substitute (1) into(2)
X+2=x2+5x+6
Collect like terms
X2+5x-x+6-2=0
X2+4x+4=0
X2+2x+2x+4=0
X(x+2)+2(x+2)=0
(X+2)(x+2)=0
X+2=0
Substrate 2 from both sides
X=-2
X+2=0
X=-2
Let's substitute the value of x into (1)
y=x+2
y=-2+2
Y=0(twice)
Answer:
2 should be distributed as 2y + 16; y = 8
Step-by-step explanation:
We have to distribute 2, then:
Now we have to sum (-2y) in both sides of the equation:
Finally we have to divide both sides of the equation in 2:
Then the answer is 2 should be distributed as 2y + 16; y = 8
Hope this helps.
