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3 years ago

Solve the equation on the interval [0,2pi) 7sec x-7=0

Mathematics

1 answer:

never [62]3 years ago

3 0

Answer:

2π or 0π are the only points that satisfy the expression, but since the restriction is 0 <= x < 2π

the answer would be 0π

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Solve 2×+ 4y=10 2×+ 4y= -10

lisabon 2012 [21]

Cannot Be Solved It Has No Solution

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3 years ago

I NEED HELP PLEASE, THANK YOU! :)

Dima020 [189]

Step-by-step explanation:

Point B(2, 8) reflect to x-axis

It means the x value won't change, the only thing that will change is the y value.

According to it, we can know that B' is (2, -8)

(2, -8) → (-8, 2+4) = (-8, 6) = B''

6 0

3 years ago

Read 2 more answers

from the edge of a 486-foot cliff, peyton shot an arrow over the ocean with an initial upward velocity of 90-feet per second

anygoal [31]

Answer:

9 seconds

Step-by-step explanation:

The complete question is

The altitude of an object, d, can be modeled using the equation below:

d=-16t^2 +vt+h

from the edge of a 486 foot cliff, Peyton shot an arrow over the ocean with an initial upward velocity of 90 feet per second. In how many seconds will the arrow reach the water below?

Let

d ----> the altitude of an object in feet

t ---> the time in seconds

v ---> initial velocity in ft per second

h ---> initial height of an object in feet

we have

$d=-16t^2 +vt+h$

we know that

When the arrow reach the water the value of d is equal to zero

we have

$v=90\ ft/sec$

$h=486\ ft$

$d=0\ ft$

substitute the values and solve for t

$0=-16t^2 +(90)t+486$

$-16t^2+90t+486=0$

Multiply by -1 both sides

$16t^2-90t-486=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$a=16\\b=-90\\c=-486$

substitute in the formula

$t=\frac{90(+/-)\sqrt{-90^{2}-4(16)(-486)}}{2(16)}$

$t=\frac{90(+/-)\sqrt{39,204}}{32}$

$t=\frac{90(+/-)198}{32}$

$t_1=\frac{90(+)198}{32}=9\ sec$

$t_2=\frac{90(-)198}{32}=-3.375\ sec$

the solution is t=9 sec

see the attached figure to better understand the problem

4 0

3 years ago

Help me please I don’t understand how to find the parallel or perpendicular

andreev551 [17]

Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept

So remember that parallel lines have the same slope, while perpendicular lines have slopes that are negative reciprocals to each other. But first, we have to find out the slope of the original equation. The easiest method to find the slope is to convert this standard form equation to slope-intercept form.

Firstly, subtract 6x on both sides of the equation: $-4y=-6x-3$

Next, divide both sides by -4 and your slope-intercept form is $y=\frac{3}{2}x+\frac{3}{4}$

Now, looking at our slope-intercept form we see that the slope of the original equation is 3/2. Using what we know about parallel and perpendicular lines, the slope of a parallel line is 3/2 and the slope of a perpendicular line is -2/3

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3 years ago

You visit a farm and notice that white chickens lay white eggs and colored chickens lay colored eggs, so you decide that only wh

Kitty [74]

Answer:

This is called an Inductive reasoning.

Step-by-step explanation:

It is a logical process in which a number of premises all believed true combine to come up with specific conclusions. This is a generalisation based on observations.

Hope it helps.

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3 years ago