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3 years ago

Solve the equation on the interval [0,2pi) 7sec x-7=0

Mathematics

1 answer:

never [62]3 years ago

3 0

Answer:

2π or 0π are the only points that satisfy the expression, but since the restriction is 0 <= x < 2π

the answer would be 0π

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Convert fraction to decimal

Gennadij [26K]

Where’s the question

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3 years ago

1. The formula for the velocity of an object is d=v/t, where v is the object, d is the distance traveled, and t is the time the

Arlecino [84]

Answer:

you need to isolate t or time

you need to know distance between sun and earth and velocity of them in order to calculate how long it takes for light to travel from the Sun to Earth

Step-by-step explanation:

$t*(d)=(v/t)*t\\td= v\\\\\frac{td}{d} =v/d \\t=v/d$

to find time you multiply t to both sides then you cancel t from where velocity is and you get velocity by itself

now you mulipy d to both side to get v over d and time by itself

6 0

3 years ago

-412-(-223) worked out

shutvik [7]

Answer:

-189

Step-by-step explanation:

Remember to follow the rules of signs:

- If there are two positive signs next to each other, you add:

- If there is one negative sign and one positive sign next to each other, you subtract.

- If there is two negative signs next to each other, you add:

- 412 - (-223) = -412 + 223

Subtract:

223 - 412 = -189

-189 is your answer.

5 0

4 years ago

Read 2 more answers

Write a system of linear equations for the graph below

Oliga [24]

1q+2x-1 liner #1 liner # is 18% one

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4 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

3 years ago