If John charge $12 then he has 14 students, and he gets $ 14*12,
If he increases on $2(12+2) , he loses 1 student (14-1), gets (12+2)*(14-1)
if he increases on he loses 2 students (14-2) gets (12+2*2)(14-2)
2+2 (12+2*2)
if he increases 2*3 he loses 3 students, (14-3) gets (12+2*3)(14-3)
2x*3 (12+2*3)
and so on......
if he increases 2*x, he loses x students, (14-x)left, gets (12+2x)(14-x)
(12+2x)
So , his revenue in general =
(12+2x)(14-x)=12*14-12x+28x-2x²=-2x²+16x+168
<em> I think it should look like this
</em>c(x)= -2x²+16x+168
Answer:
y = 9,958(0.972)^t
Step-by-step explanation:
From point to point, the difference in days is always constant (10 days), but the difference between estimated number of bees is not constant.
10000 - 7500 = 2500
7500 - 5600 = 1900
5600 - 4200 = 1600
4200 - 3200 = 1000
3200 - 2400 = 800
Therefore, the data don't fit a line.
From the other two options:
y = 9,958(0.972)^t
y = 0.972(9,958)^t
only the first one has sense, because its initial amount of bees is 9,958 (near to 10,000) and in the second option is 0.972.
Answer:
i believe it's the first one
Step-by-step explanation: