Answer:
(f o g)(4)=27
Step-by-step explanation:
(f o g)(4)=2x+5
f(g(4))=2x+5
f(4²-2(4)+3)=2x+5
f(16-8+3)=2x+5
f(8+3)=2x+5
f(11)=2x+5
f(11)=2(11)+5
f(11)=22+5
f(11)=27
Therefore, (f o g)(4)=27
A radius of a circle or sphere is any of the line segments from its center to its perimeter, and in more modern usage, it is also their length. Set up the formula for the area of a circle. The formula is A = π r 2 it equals the area of the circle, and r equals the radius.
Solve for the radius.
Plug the area into the formula.
Divide the area by.
Take the square root.
A) The given equation has no solution. The absolute value cannot be negative, but must be -9 in order for the equation to be satisfied.
b) |x -7| = 2 . . . . . . . the equation
Solution 1:
-2 = x -7
5 = x . . . . . . add 7
Solution 2
x -7 = 2
x = 9 . . . . . . add 7
The two numbers are {5, 9}
Answer:
1.x=41
x=9
Step-by-step explanation:
1.x-7=34
x=41
3x-7=20
3x=27
x=9
The atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit (amu, also known as daltons, D). The atomic mass is a weighted average of all of the isotopes of that element, in which the mass of each isotope is multiplied by the abundance of that particular isotope. (Atomic mass is also referred to as atomic weight, but the term "mass" is more accurate.)
