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PilotLPTM [1.2K]
3 years ago
12

Find the product. (−7)(8) =

Mathematics
1 answer:
Inga [223]3 years ago
4 0

Answer:-56

Step-by-step explanation:The product is your answer

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(2x + 35)=(5x-22) what’s x
finlep [7]

Answer:

x=19

Step-by-step explanation:

5 0
3 years ago
Numbers 38 and 40 pls and thanks
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8 0
3 years ago
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Use distance formula d=√(X2 – X1 )2 + (X2 – X1 )2, calculate the distance r from the origin to the point r (-2, √5).
lesya692 [45]
d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} \\d = \sqrt{(\sqrt{5} - (-2))^{2} + (\sqrt{5} - (-2))^{2}} \\d = \sqrt{(\sqrt{5} + 2)^{2} + (\sqrt{5} + 2)^{2}} \\d = \sqrt{(4 + 4\sqrt{5} + 5) + (4v + 4\sqrt{5} + 5)} \\d = \sqrt{0 + 0} \\d = \sqrt{0} \\d = 0
7 0
4 years ago
Look at the following expression.
kow [346]

Answer:

f

f

f

f

Step-by-step explanation:

what if w=3 or 8

8 0
3 years ago
I walk each day to school. By what percentage would I need to increase my usual average speed in order for the journey to take 2
lesya692 [45]

Answer:

25%

Step-by-step explanation:

Let v, t be the current average speed and the time taken to reach the school respectively.

As distance = speed x time, so,

distance, d=vt...(i)

Let V be the new average speed in order to to take 20% less time than t.

So, time taken with speed V = t-20% of t = t- 0.2t= 0.8t

As distance is constant, so

d= V(0.8t)= 0.8Vt

hBy using equation (i), we have

0.8Vt = vt

0.8 V = v

V= v/0.8=1.25v

Therefore, the percentage increase in the average speed = \frac{V-v}{v}\times 100

=\frac{1.25v-v}{v}\times 100

=25%

Hence, the percentage increase in the average speed is 25%.

8 0
3 years ago
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