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Alexxx [7]
3 years ago
12

b) The sum of 9 times a larger number and twice a smaller is 6. The difference of 3 times the larger and the smaller is 7. Compu

te the numbers. (10marks) Remarks: These questions involved several scenarios 1. Assign the variables -2marks 2. Assumptions of the context of the two numbers -2marks 3. Apply linear systems -2marks 4. Compute using the applicable method of system of linear system -2marks 5. Compute both numbers from above-2marks
Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

1) let the larger number be x and the smaller is y

2) 9x + 2y = 6

3x - y = 7

3) 9x+2y=6 and 9x -3y = 21

5y = -15

y= -3

5)

3x=4

x=4/3

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Step-by-step explanation:

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3 years ago
A Ferris Wheel 22.0m in diameter rotates once every 12.5s. What is the ratio of a persons apperenet weight to her real weight (a
AnnZ [28]
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a = omega^2*r 

omega and r in terms of given data: 
omega = 2*Pi/T 
r = d/2 

Thus: 
a = 2*Pi^2*d/T^2 

What forces cause this acceleration for the passenger, at either top or bottom? 

At top (acceleration is downward): 
Weight (m*g): downward 
Normal force (Ntop): upward 

Thus Newton's 2nd law reads: 
m*g - Ntop = m*a 

At top (acceleration is upward): 
Weight (m*g): downward 
Normal force (Nbottom): upward 

Thus Newton's 2nd law reads: 
Nbottom - m*g = m*a 

Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame: 
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Nbottom = m*(g + a) 


Substitute a: 
Ntop = m*(g - 2*Pi^2*d/T^2) 
Nbottom = m*(g + 2*Pi^2*d/T^2) 

We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground): 
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g) 
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g) 

Simplify: 
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Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2) 

Data: 
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Results: 
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