Express in simplest a+bi form: Square root of 1b + Square root of -1b

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

5 0

Express in simplest a+bi form: Square root of 1b + Square root of -1b

$\sqrt{1b} + \sqrt{-1b}$

Lets simplify $\sqrt{-b}$

We know $\sqrt{-1} = i$

$\sqrt{-b} =i\sqrt{b)$

We cannot simplify $\sqrt{1b}$

$\sqrt{1b} + \sqrt{-1b}$

$\sqrt{1b} + i\sqrt{b}$

So a + ib form is $\sqrt{1b} + i\sqrt{b}$

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Which of the following is not a true statement about pi?

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Answer:

Option D.The ratio of the radius of a circle to its circumference

Step-by-step explanation:

<em>Verify each statement</em>

A) The ratio of the circumference of a circle to its diameter

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$C=\pi D$

$\pi=C/D$

B) Approximated to be 3.14

The statement is True

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C) Approximated to be 22/7

The statement is True

Because

$\frac{22}{7}=3.1423$

D) The ratio of the radius of a circle to its circumference

The statement is not True

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4 0

2 years ago

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Doss [256]

1a) The function has arrows on both ends and no place in the middle where it is not defined. Its domain is ...
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1b) The function gives no output values below -3, but it gives output values of -3 and all above that. Its range is ...
y ≥ -3

1c) For values of x less than -1, the function's output is 1. This matches g(x) and s(x). At x=0, the function's output is -3, which only matches g(x). The appropriate choice is ...
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2b) The function is only defined for 0 ≤ x < 8. This is its domain.

3) A definition might be ...
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