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3 years ago

How to prove points belong to the same circle

1 answer:

4 0

Not sure what the mess above me says, but basically as long as you have an equation for the circle, you can plug the coordinates of your point into the x and y values of the equation and see if it equals out. If you don’t have an equation, you can just make one. Use (f-k)^2+(x-h)^2=r^2 where h and k are the coordinates of the center of the circle and r is the radius. Hope this helps!

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Simplify the square root of 3 times the fifth root of 3.

bogdanovich [222]

Answer:

<h2>Three to the three fifths power.</h2>

Step-by-step explanation:

The given expression is

$\sqrt{3\sqrt[5]{3} }$

To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:

$\sqrt[n]{x^{m}}=x^{\frac{m}{n}}$

Applying the property, we have:

$\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}$

Now, we multiply exponents:

$(3(3)^{\frac{1}{5}})^{\frac{1}{2}}\\3^{\frac{1}{2}}3^{\frac{1}{10}}$

Then, we sum exponents to get the simplest form:

$3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}} \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }$

Therefore, the right answer is three to the three fifths power.

3 0

3 years ago

Read 2 more answers

Find the second derivative of 2x^3-3y^2=8

Umnica [9.8K]

Answer:

$\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

Step-by-step explanation:

Find the first implicit derivative using implicit differentiation

$2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}$

Use the substitution of dy/dx to find the second derivative (d²y/dx²)

$\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

5 0

2 years ago

Would the answer be 12.5

Schach [20]

Yes, it would be 12.5.

5 0

3 years ago

An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $1790 and his st

stiv31 [10]

Answer:

20.7%

Step-by-step explanation:

Amount of stock increased in Company A = 20% of 1790

= 0.20 * 1790 = $ 358

Investor's stock in company A this year = 1790 + 358 = $ 2148

Amount of stock increased in Company B = 22% of 1000

= 0.22 * 1000= $ 220

Investor's stock in company B this year = 1000 + 220 = $ 1220

Total amount in investor's stock account = 2148 + 1220 = $ 3368

Increased amount = 3368 - 2790 = $ 578

Increase percentage = $\frac{578}{2790}*100$ = 20.71

= 20.7%

7 0

3 years ago

Read 2 more answers

Would g this be (2,-3)?

Anna [14]

Answer:

yes it is (2,-3)

Step-by-step explanation:

if you see in there where both of the lines intersect or touch each other (the gray dot)

the point of intersect is at (2, -3)

3 0

3 years ago