Answer:
Correct option is
C
36.25
Modal class =30−40
So we have, l=30,f0=12,f1=32,f2=20 and h=10
⇒ Mode=l+2f1−f0f2f1−f0×h
=30+2×32−12−2032−12×10
=30+6.25
=36.25
∴ Mode =36.25
Work problems are solved by first figuring out how much of the job they can do in each hour. Shawn can do 1/4 of the job in an hour and Ellie can do 1/6 of the job in an hour. 1/6+1/4=2/12+3/12=5/12. This means that they can do 5/12 of the job an hour. This means that together they can do the job in 2 2/5 hours. The foreman is obviously wrong because first of all Shawn can do it alone in 4 hours, so with Ellie he will do it faster, and second of all 2 2/5<5. Hope this helped!
Answer:
A. 
B. 42.2 million
Step-by-step explanation:
Part A:
Given:
Newspapers circulated in year 2004, 
Newspapers circulated in year 2014, 
Let the time 
start at the year 2004. So, 
For the year 2014, 
Therefore, linear relationship between newspapers circulated and time passed since 2004 is given as:
Therefore, the equation describing the relationship is:
Part B:
For the year 2018, 
Plug in 14 for in the above equation and solve for 
. This gives,
Therefore, in the year 2018, the newspaper circulation will be 42.2 million.
Answer: The numbers are 14, 16 and 18.
Step-by-step explanation: First thing to note is that consecutive even numbers have a difference of 2 units between every two terms. That is, if the first number is a, the next would be a + 2, and the next would be a + 4, and so on.
Therefore the three consecutive even numbers shall be a, a + 2, and a + 4.
Our equation now becomes;
a + a + 2 + a + 4 = 48
3a + 6 = 48
Subtract 6 from both sides of the equation
3a = 42
Divide both sides of the equation by 3
a = 14
Therefore, the numbers are 14, 16 and 18.
