Answer:
- r = 12.5p(32 -p)
- $16 per ticket
- $3200 maximum revenue
Step-by-step explanation:
The number of tickets sold (q) at some price p is apparently ...
q = 150 + 25(20 -p)/2 = 150 +250 -12.5p
q = 12.5(32 -p)
The revenue is the product of the price and the number of tickets sold:
r = pq
r = 12.5p(32 -p) . . . . revenue equation
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The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...
p = (0 +32)/2 = 16
The theater should charge $16 per ticket.
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Maximum revenue will be found by using the above revenue function with p=16.
r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue
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<em>Additional comment</em>
The number of tickets sold at $16 will be ...
q = 12.5(32 -16) = 200
It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.
We know that
if <span>90° < θ < 180°
</span>then
θ--------------> belong to the second quadrant
so
tan θ is negative
sin² θ + cos² θ=1----------> sin² θ=1-cos² θ----->sin² θ=1-(-2/9)²
sin² θ=1-(4/81)------> 77/81----------> sin θ=√(77/81)------> √77/9
sin θ=(√77)/9
tan θ=sin θ/cos θ------> [(√77)/9]/[-2/9]-------> -√77/2
the answer is the option
<span>A) -77sqroot/2</span>
There is a five year difference and and a 12 million people difference so if you divide 12 million by 5 you get the answer 2,400,000 per year increase in population
Answer:
The answer to your question is 9
Step-by-step explanation:
Data
Paramecium's length = 4.2 x 10⁻⁴ m
Ant's length = 3.8 x 10⁻³ m
Process
If we need to know how much longer is the ant than the paramecium, we just need to divide the ant's length by the paramecium's length.
Times that the length of the ant is longer than the paramecium length =
Simplification and result
9
