Answer: A) .1587
Step-by-step explanation:
Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.
i.e. 
and 
Let x denotes the amount of soda in any can.
Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.
Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =
![P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587](https://tex.z-dn.net/?f=P%28x%3E12.50%29%3D1-P%28x%5Cleq12.50%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B12.50-12.30%7D%7B0.20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.8413%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1587)
Hence, the required probability= A) 0.1587
The answer is "It was A Jab Well Done" You have to finish the whole sheet to get the answer
Answer:
The bottom right histogram is the correct one.
Step-by-step explanation:
Carrots weight 40-49 kg = 2
... of weight 50-59 = 6
... of weight 60-69 = 4
.. of weight 70-79 = 1
Answer:
A. y= 2(x - 2)2 + 4
Step-by-step explanation:
vertex having an x value of 2 means the phrase in paren must be x - 2.
This eliminates B and D
vertex having a y value of 4 is of no help as the remaining two equations will result in 4 if the x term is 2
plugging in x = 3 makes y = 6 in equation A, but not in equation C where y = 10
Answer:
1 and 3
This is because they go all the way through the circle and the origin touches the inside if the circle the uninscribed angle will also be half of the amount of the inscribed angle if you have a question on that also.
Hope this helps :)
