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il63 [147K]
4 years ago
13

Vlad spent 20 minutes on his history homework and then completely solved x math problems that each took 2 minutes to complete. W

hat is the equation that can be used to find the value of y, the total time that Vlad spent on his homework, and what are the constraints on the values of x and y?
1. y=2x+20; x is any integer greater than or equal to 0, and y is an integer greater than or equal to 20.

2. y=2x+20; x is any real number greater than or equal to 0, and y is any real number greater than or equal to 20.

3. y=20x+2; x is any integer greater than or equal to 0, and y is an integer greater than or equal to 20.

4. y=20x +2; x is any real number greater than or equal to 0, and y is any real number greater than or equal to 20.
Mathematics
2 answers:
MAXImum [283]4 years ago
5 0
I believe #2 would be the best answer. Either that or #1.
Genrish500 [490]4 years ago
5 0

Answer:

y=2x+20; x is any integer greater than or equal to 0, and y is an integer greater than or equal to 20

Step-by-step explanation:

Vlad spent 20 minutes on his history homework and then completely solved x math problems that each took 2 minutes to complete

Let x be the number of math problems

Initial time spent = 20 minutes

Equation is y=mx+b

each problem took 2 minutes to complete.. so m=2

y=mx+b

y=2x+20

y=2x+20; x is any integer greater than or equal to 0, and y is an integer greater than or equal to 20

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Solve for x. Show all your work
olasank [31]

42°

Step-by-step explanation:

\angle BAE =180\degree -132\degree

(Angles in linear pair)

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\angle ABE = 180\degree-(48\degree+90\degree)

(Angle sum postulate of a triangle)

\implies\angle ABE = 180\degree-138\degree

\implies\angle ABE = 42\degree

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(corresponding angles)

\implies x\degree=\angle CDE

(vertical angles)

\implies x\degree=42\degree

\implies x=42

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2 years ago
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Nookie1986 [14]
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4 0
3 years ago
In rectangle ABCD, point E lies halfway between sides AB and CD and halfway between sides AD and BC. If AB=6 and BC=9, what is t
zloy xaker [14]

Answer:

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max2010maxim [7]

Step-by-step explanation:

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Hope this helps!

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