Pretty sure the answer would be 1/A^4
Answer:
The complete solution is
Step-by-step explanation:
Given differential equation is
3y"- 8y' - 3y =4
The trial solution is

Differentiating with respect to x

Again differentiating with respect to x

Putting the value of y, y' and y'' in left side of the differential equation


The auxiliary equation is




The complementary function is

y''= D², y' = D
The given differential equation is
(3D²-8D-3D)y =4
⇒(3D+1)(D-3)y =4
Since the linear operation is
L(D) ≡ (3D+1)(D-3)
For particular integral

[since
]
[ replace D by 0 , since L(0)≠0]

The complete solution is
y= C.F+P.I

Answer:
not factorable
Step-by-step explanation:

The easiest way to factor is to find two numbers of the "a" value (the coefficient before
) and the factors of the c value (10) that ADD up to give you -9, in this case it would be:
1 -10 --> 1(-10) gives you -10
1 -1 --> 1(-1) gives you -1
adding these together -10 + (-1) = -11 which does not equal -9.
You could stop here and conclude that this is not factorable by inspection.
Another method: using the quadratic formula to find its roots.
Roots:
and 
Answer:

Step-by-step explanation:
step 1
Find the slope of the perpendicular line
we know that
If two lines are perpendicular, then their slopes are opposite reciprocal
(the product of their slopes is equal to -1)
In this problem
we have

The equation of the given line is 
so
the slope of the perpendicular line to the given line is

step 2
Find the equation of the line in point slope form

we have


substitute

Convert to slope intercept form

Distribute right side


