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Nostrana [21]
2 years ago
5

Solve for x. Show all your work

Mathematics
1 answer:
olasank [31]2 years ago
3 0

42°

Step-by-step explanation:

\angle BAE =180\degree -132\degree

(Angles in linear pair)

\angle BAE =48\degree

\angle AEB =90\degree..(\because \overrightarrow{EC}\perp\overrightarrow{ED})

\angle ABE = 180\degree-(48\degree+90\degree)

(Angle sum postulate of a triangle)

\implies\angle ABE = 180\degree-138\degree

\implies\angle ABE = 42\degree

\angle CDE =\angle ABE = 42\degree

(corresponding angles)

\implies x\degree=\angle CDE

(vertical angles)

\implies x\degree=42\degree

\implies x=42

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Pretty sure the answer would be 1/A^4
3 0
3 years ago
Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie
melamori03 [73]

Answer:

The complete solution is

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

y = e^{mx}

Differentiating with respect to x

y'= me^{mx}

Again differentiating with respect to x

y''= m ^2 e^{mx}

Putting the value of y, y' and y'' in left side of the differential equation

3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0

\Rightarrow 3m^2-8m-3=0

The auxiliary equation is

3m^2-8m-3=0

\Rightarrow 3m^2 -9m+m-3m=0

\Rightarrow 3m(m-3)+1(m-3)=0

\Rightarrow (3m+1)(m-3)=0

\Rightarrow m = 3, -\frac13

The complementary function is

y= Ae^{3x}+Be^{-\frac13 x}

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)    

For particular integral

y_p=\frac 1{(3D+1)(D-3)} .4

    =4.\frac 1{(3D+1)(D-3)} .e^{0.x}    [since e^{0.x}=1]

   =4\frac{1}{(3.0+1)(0-3)}      [ replace D by 0 , since L(0)≠0]

   =-\frac43

The complete solution is

y= C.F+P.I

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

4 0
3 years ago
Factor each polynomial x^2-9x+10 <br> Show your work
jok3333 [9.3K]

Answer:

not factorable

Step-by-step explanation:

x^{2}  - 9x +10\\

The easiest way to factor is to find two numbers of the "a" value (the coefficient before x^{2}) and the factors of the c value (10) that ADD up to give you -9, in this case it would be:

1          -10  --> 1(-10) gives you -10

1           -1    --> 1(-1) gives you -1

adding these together -10 + (-1) = -11 which does not equal -9.

You could stop here and conclude that this is not factorable by inspection.

Another method: using the quadratic formula to find its roots.

Roots: (\frac{9-\sqrt{41} }{2}, 0) and (\frac{9+\sqrt{41}}{2}, 0)

7 0
2 years ago
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Korolek [52]

Answer:

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Step-by-step explanation:

step 1

Find the slope of the perpendicular line

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal

(the product of their slopes is equal to -1)

In this problem

we have

y=3x+1

The equation of the given line is m=3

so

the slope of the perpendicular line to the given line is

m=-\frac{1}{3}

step 2

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=-\frac{1}{3}

(x1,y1)=(6,2)

substitute

y-2=-\frac{1}{3}(x-6)

Convert to slope intercept form

y=mx+b

Distribute right side

y-2=-\frac{1}{3}x+2

y=-\frac{1}{3}x+2+2

y=-\frac{1}{3}x+4

6 0
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kipiarov [429]
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