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3 years ago

What is the equation of the inverse of H(X)=5X+2

1 answer:

4 0

The inverse is the symmetrical function relatively to the function y=x. So, it basically means, that to find the inverse, you just need:
1. Switch x and y (or f(x)): x = 5H(x) + 2
2. Solve for y again (or for f(x)):
5H(x) = x -2
H(x) = (x-2)/5
This is the inverse.

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Area of it plssssssssssssSSssssssSSSsSSSSs

Vaselesa [24]

Answer:

40units²

Step-by-step explanation:

find the shapes you know the formula of. There's two shapes a rectangle and a trapezoid.

do the formula for rectangle

A = bh

A = 8×2

A = 16

Now the formula for Trapezoid

A = 1/2h(b+b)

A = 1/2×4(4+8)

A = 1/2×4(12)

A = 1/2(48)

A = 24

16+24 = 40

5 0

3 years ago

A rectangular pool is 20 ft wide and 50 ft long. the pool is surrounded by a walkway. the walkway is the same width all the way

Ratling [72]

50wideis the walkway

8 0

3 years ago

Please help. How do you find cosine, sine, cosecant and secant with this triangle?

Veseljchak [2.6K]

Hi there! You have to remember these 6 basic Trigonometric Ratios which are:

sine (sin) = opposite/hypotenuse
cosine (cos) = adjacent/hypotenuse
tangent (tan) = opposite/adjacent
cosecant (cosec/csc) = hypotenuse/opposite
secant (sec) = hypotenuse/adjacent
cotangent (cot) = adjacent/opposite
cosecant is the reciprocal of sine
secant is the reciprocal of cosine
cotangent is the reciprocal of tangent

Back to the question. Assuming that the question asks you to find the cosine, sine, cosecant and secant of angle theta.

What we have now are:

Trigonometric Ratio
Adjacent = 12
Opposite = 10

Looks like we are missing the hypotenuse. Do you remember the Pythagorean Theorem? Recall it!

a²+b² = c²

Define that c-term is the hypotenuse. a-term and b-term can be defined as adjacent or opposite

Since we know the value of adjacent and opposite, we can use the formula to find the hypotenuse.

10²+12² = c²
100+144 = c²
244 = c²

Thus, the hypotenuse is:

$\large \boxed{c = 2 \sqrt{61} }$

Now that we know all lengths of the triangle, we can find the ratio. Recall Trigonometric Ratio above! Therefore, the answers are:

cosine (cosθ) = adjacent/hypotenuse = 12/(2√61) = 6/√61 = (6√61) / 61
sine (sinθ) = opposite/hypotenuse = 10/(2√61) = 5/√61 = (5√61) / 61
cosecant (cscθ) is reciprocal of sine (sinθ). Hence, cscθ = (2√61/10) = √61/5
secant (secθ) is reciprocal of cosine (cosθ). Hence, secθ = (2√61)/12 = √61/6

Questions can be asked through comment.

Furthermore, we can use Trigonometric Identity to find the hypotenuse instead of Pythagorean Theorem.

Hope this helps, and Happy Learning! :)

5 0

3 years ago

Ralph has sliced a pizza using straight line cuts through the center of the pizza. the slices are not exactly the same size. Ral

Stels [109]

x=18 the angles are 36 and 54

6 0

3 years ago

Read 2 more answers

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

Equation Solving

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$