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Anvisha [2.4K]
3 years ago
14

Two horses start a race at the same time. Horse A gallops at a steady rate of 32 feet per second and Horse B gallops at a steady

rate of 28 feet per second. After 5 seconds, how much farther will Horse A have traveled? Explain your reasoning. *
Mathematics
1 answer:
zlopas [31]3 years ago
5 0

Answer:

Horse A will have traveled 20 feet farther

Step-by-step explanation:

Horse A has traveled 160 feet in 5 seconds, and Horse B has traveled 140 feet in 5 seconds, and 160-140=20

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Simplify the expression below.<br> (6-3)(66)
irinina [24]

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198

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Solve for the sqrt(x-2)+8=x
kirza4 [7]
<h3>Answer:  x = 11</h3>

==============================================

Work Shown:

\sqrt{x-2}+8=x\\\sqrt{x-2}=x-8\\\left(\sqrt{x-2}\right)^2=(x-8)^2 \text{ square both sides}\\x-2=x^2-16x+64\\0=x^2-16x+64-x+2\\0=x^2-17x+66\\x^2-17x+66 = 0\\(x-11)(x-6) = 0\\x-11 = 0 \text{ or } x-6 = 0\\x = 11 \text{ or } x = 6\\

Those are the two possible solutions . We need to check each possible solution.

Plug in x = 11 then simplify. If we get the same number on both sides, then x = 11 is confirmed.

\sqrt{x-2}+8=x\\\sqrt{11-2}+8=11\\\sqrt{9}+8=11\\3+8=11\\11=11\\

We get 11 on both sides, so the solution x = 11 is confirmed.

Repeat for x = 6 as well

\sqrt{x-2}+8=x\\\sqrt{6-2}+8=6\\\sqrt{4}+8=6\\2+8=6\\10=6\\

We do not get the same thing on both sides, so x = 6 is not a solution. We consider this extraneous.

4 0
3 years ago
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