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Bingel [31]
3 years ago
14

Pleaseee help me....what will the y-coordinate of b' if ab is dilated by a factor of 2/5, centered at the origin. A=(2,2) B=(10,

2)

Mathematics
2 answers:
sdas [7]3 years ago
3 0

Answer:

The y-coordinate of B' is equal to 2

Step-by-step explanation:

step 1

Find the distance of AB

AB=10-2=8\ units

step 2

Find the length of A'B'

Multiply the length of AB by the scale factor

A'B'=8*\frac{2}{5}= 3.2\ units

step 3

Find the midpoint AB

M=(\frac{2+10}{2},\frac{2+2}{2} )

M=(6,2)

step 4

<em>Find the x-coordinate of B'</em>

The x-coordinate of B' is equal to the x-coordinate of midpoint plus the semi distance A'B'

6+\frac{3.2}{2}=6+1.6=7.6

<em>Find the y-coordinate of B'</em>

The y-coordinate of B' is equal to 2 (because is a horizontal line)

xenn [34]3 years ago
3 0

Answer:

The y-coordinate of point B' is \frac{4}{5} or 0.8.

Step-by-step explanation:

If a figure dilated by scale factor k, centered at the origin, then

(x,y)\rightarrow(kx,ky)

It is given that the coordinates of A are (2,2) and coordinates of B are (10,2).

The scale factor is \frac{2}{5}, so the coordinates of image are

A(2,2)\rightarrowA'(\frac{2}{5}(2),\frac{2}{5}(2))\Rightarrow A'(\frac{4}{5},\frac{4}{5})=A'(0.8,0.8)

B(10,2)\rightarrowB'(\frac{2}{5}(10),\frac{2}{5}(2))\Rightarrow B'(4,\frac{4}{5})=B'(4,0.8)

Therefore the y-coordinate of point B' is \frac{4}{5} or 0.8.

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Problem 1

Answer: <u>Yes</u> a triangle can be formed with side lengths 5,5,3

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Explanation:

Take any two sides and add them up. If we get a sum larger than the third side, then a triangle is possible. This is the triangle inequality theorem.

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Yes it is true that

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Imagine you had 3 strips of paper that were 7 inches, 8 inches and 15 inches long. The 7 and 8 inch strips add to 15 inches, but those two smaller strips only form a straight line. We cannot pull them so a triangle forms. If we did, then the third side would be smaller than 15 inches. This is one way to get hands on to see why the triangle inequality theorem works.

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