Answer:
Just to recap, an equation has no solution when it results in an incorrect "equation".
For example:
Equation: x+3 = x+4
Subtract x: 3 = 4???
But clearly, 3 is not equal to 4, so this equation has NO SOLUTION.
Now onto our problem:
13y+2-2y = 10y+3-y
11y+2 = 9y+3
2y=1
y=1/2
9(3y+7)-2 = 3(-9y+9)
27y+61 = -27y+27
54y = -34
y = -34/54
32.1y+3.1+2.4y-8.2=34.5y-5.1
34.5-5.1=34.5y-5.1
5.1=5.1
infinite solutions
5(2.2y+3.4) = 5(y-2)+6y
11y+17 = 11y-10
17 = -10??
That's not true, so the option "5(2.2y+3.4) = 5(y-2)+6y" has no solution.
Let me know if this helps
Given the function:
The function can also be written as:
The range of the function will be all set of y values.
To find the range, let's graph the function below.
We have:
From the graph above, all possibe y values range from 0 to infinity.
Therefore, the range of the function is from zero infinity.
In interval notation:
Range = (0, +∞)
ANSWER:
4. (0, +∞)
Little of, not in plethora, small numbered
Answer:
x = 37 y = 12
Step-by-step explanation:
Let x be one number
Let y = other number
x+y = 49
x-y = 25
Add the equations together
x+y = 49
x-y = 25
---------------
2x = 74
Divide by 2
2x/2 = 74/2
x =37
x+y = 49
37+y = 49
Subtract 37 from each side
37+y-37 = 49-37
y = 12
