Answer:
11.33 degrees
Step-by-step explanation:
What exactly are you finding
Answer:
an = (1 + 2·(n - 1))/2^(n - 1) = 2^(1 - n)·(2·n - 1)
sn = 6 - 2·0.5^n·(2·n + 3)
Answer:
L.H.S.
= (cos5a.sin2a-cos4a.sin3a)/ (sin5a.sin2a-cos4a.cos3a)
Multiply numerator and denominator by 2.
= 2(cos5a.sin2a - cos4a.sin3a) / 2(sin5a.sin2a - cos4a.cos3a)
= (2cos5a.sin2a - 2cos4a.sin3a)/
(2sin5a.sin2a - 2cos4a.cos3a) = [sin(5a+2a)-sin(5a-2a)-sin(4a+3a)
+sin(4a-3a)]/[cos(5a-2a)-cos(5a+2a)-sin(4a-3a) +cos(4a+3a)]
= (sina - sin3a)/(cso3a-cosa)
= (-2cos2a.sina)/(-2sin2a.sina)
= cos2a/sin2a
= cot2a
= R.H.S.
Complete Question:
The complete question is shown on the first uploaded image
Answer:
The probability that the random you randomly select species that are greater than 200 kg is = 7/62
Step-by-step explanation:
Step One: Load the data set in to the R work space
data(mammals,package="MASS")
attach(mammals)
Step 2 : Obtain the list of the species that are greater than 200 and store it on y variable.
y <- subset(mammals,body>200)
Step Three : Obtain the total size
nrow(mammals)
Step Four : Obtain the sum of species greater than 200
sum(body > 200)
total size = 62
size with body > 200 = 7
hence
required probability = 7/62