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viktelen [127]
3 years ago
8

At the zoo, there are 3 fewer ferrets than twice the number of tigers. If there are 21 ferrets, what's an equation for the numbe

r of tigers at the zoo?
What is the number of ferrets?​
Mathematics
2 answers:
damaskus [11]3 years ago
6 0

Answer:

That other person deserves brainliest. also why are ferrets in a zoo? they are pets

Step-by-step explanation:

sleet_krkn [62]3 years ago
4 0

12x2-3=21

this would be your equation because there are 12 tigers

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Which of the following expressions is equivalent to 20 + 30x?​
Nostrana [21]
You have to get X all by itself so you divide 20 and 30 which gives you a fraction. X= 20/30
Then = 2/3
4 0
2 years ago
Find the domain and range of the function represented by the graph.
True [87]

Answer:

C

Step-by-step explanation:

The domain of this function is [-4,2], as it is shown in the graph that x is only within this interval. The range of this function is [-4,4], as the smallest value of y is -4 and the largest value of y is 4, and y takes every possible values between them.

4 0
3 years ago
What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?
Trava [24]

Answer:

\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}

Step-by-step explanation:

The explicit formula for a geometric sequence:

a_n=a_1r^{n-1}

a_n - n-th term

a_1 - first term

r - common ratio

r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}

We have

a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...

The common ratio:

r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}

<h2>It's not a geometric sequence.</h2>

If a_3=-\dfrac{1}{16} then the common ratio is r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}

Put to the explicit formula:

a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}

Put a_n=\dfrac{1}{1024} and solve for <em>n </em>:

-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1

\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6

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3 years ago
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Sholpan [36]
All of these answers are right
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