For
ax^2+bx+c=0
discriminatn is b^2-4ac
a=4
b=12
c=9
discriinat is
12^2-4(4)(9)=
144-144
0
the discrminat is 0
It's the first one and the last one need any more help let me know okay
Answer:
54
Step-by-step explanation:
To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.
The perimeter of the given triangle = IK + KM + MI
IK = IJ + JK = 13
KM = KL + LM = ?
MI = MN + NI ?
Let's find the length of each tangents.
NI = IJ = 5 (tangents from external point I)
JK = IK - IJ = 13 - 5 = 8
JK = KL = 8 (Tangents from external point K)
LM = MN = 14 (Tangents from external point M)
Thus,
IK = IJ + JK = 5 + 8 = 13
KM = KL + LM = 8 + 14 = 22
MI = MN + NI = 14 + 5 = 19
Perimeter = IK + KM + MI = 13 + 22 + 19 = 54
1/6 of 3/4 mile = 1/6 * 3/4 = 1/8 = 0.125 mile
The correct result would be 1/8 or 0.125 mile.
