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just olya [345]
3 years ago
14

Please help for eleven points

Mathematics
1 answer:
Arlecino [84]3 years ago
3 0

C:     B:

3       0

6       9

9        18

12       27

All you had to do was plug in the value for c or b and solve. You can tell this is most likely correct because you see patterns for both variables. C is going up by threes, while b is going up by nines.

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List the angles in order from largest to smallest. A) ∠R, ∠P, ∠Q B) ∠R, ∠Q, ∠P C) ∠Q, ∠P, ∠R D) ∠Q, ∠R, ∠P
mars1129 [50]

Answer: A

Step-by-step explanation:

Angles opposite shorter sides of a triangle are smaller, and angles opposite longer sides in a triangle are larger.

8 0
2 years ago
Will uses 3 1/4 ounces each of 5 different types to make fruit smoothies. How many ounces did he use
abruzzese [7]
3 1/4 ounces = 3.25 Ounces.

3.25 x 5 = 16.25 ounces (16 1/4 ounces)
3 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT
babymother [125]

So I believe that the position the triangle is sitting in is the original position that the question started with correct? (Wasn't sure if you moved it before the screenshot or not)

So for all three points of the triangle, move each of them 6 units to the left since the rule has (x-6). If it was x+6, it should be 6 units to the right then.

After you move it 6 units to the left, move the points (all three) 4 units down since (y-4) means moving in the y-direction downward!

That should be the new place for the triangle to be positioned.

Hope this helps!

6 0
3 years ago
How do you sketch the graph of y=(x 3)^2 6 and describe the transformation?
mr_godi [17]
This graph is a Quadratic Graph meaning it is a "U" shape. I am unable to help with the transformations since I am unaware of the signs in the problem. But I hope I helped
4 0
3 years ago
L1 : y = 2x , (2) find the equation of the line L2 perpendicular to L1 passing through the point P = (1, 2).
just olya [345]

Answer:

<h2>2y+x = 5</h2>

Step-by-step explanation:

Given the line L1 as y = 2x perpendicular to an unknown line L2 passing through the point P = (1, 2), we are to find the equation of line L2. to find the equation of the line L2, we will use the point-slope equation of a line expressed as y-y₀ = m(x-x₀)

m is the slope of the unknown line

(x₀, y₀) is the given point.

First is to get the slope of the known line:

comparing the line L1: y = 2x with the standard equation of the line y = mx+c, it can be seen that m = 2

Then we will calculate the slope of the required line.

Since L1 is perpendicular to L2, the product of their slope will be -1 i.e

mm₁ = -1 where m₁ is the slope of the required line L2.

Given m =2

m₁ = -1/m

m₁ = -1/2

Finally we will calculate the equation of line L2 by substituting the slope of line L2 and the point in the point slope equation above;

y-y₀ = m(x-x₀)

Given (x₀, y₀) = (1,2) and m₁ = -1/2

y-2 = -1/2(x-1)

open the parenthesis

y-2 = -x/2+1/2

multiply through by 2:

2y-4 = -x+1

2y+x = 1+4

2y+x = 5

<em>Hence the equation of the line L2 is 2y+x = 5</em>

<em></em>

8 0
3 years ago
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