<h2> (1 ,2) (2,-3)</h2><h2>(x1,y1) (x2, y2)</h2>
<h2> Distance formual</h2>
<h2> √(x2-x1)^+(y2-y1)^</h2>
<h2>= √(2-1)^+(-3-2)^</h2><h2>= √(1)^+(-5)^ [here square root and </h2><h2> square get cancelled]</h2><h2>= (1)+(-5)</h2><h2>= 1-5</h2><h2>= - 4</h2>
Youll have to move the decimal to the right twise on both of then them divide normally
Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.
<h3>Discriminant of a quadratic equation</h3>
Quadratic equation is an equation that has a leading degree of 2. The discriminant is used to determine the nature of the equation
If D > 0 , the roots of the quadratic equation are real and distinct.
If D < 0 , the roots of the quadratic equation are complex
Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.
Learn more on discriminant here: brainly.com/question/2507588
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The answer would be 12 to the -10 because with multiplication you you add the -4 and -6
Answer:
$13,793
Step-by-step explanation:
Kate purchased a car for $23,000. It will depreciate by a rate of 12% a year. What is the value of the car in 4 years. *
The formula for Depreciation rate =
y = a(1 - r) ^t
Where
y = Value of the car after t years
a = Initial value of the car = $23,000
t= time in years = 4 years
r = Depreciation rate = 12% = 0.12)
y = $23000 (1 - 0.12)⁴
y = $13792.99328
Approximately = $13,793:
