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algol [13]
3 years ago
11

If you mix the butter and the honey together, how many tablespoons will there be in all? Write your answer as a reduced fraction

in the form a/b. Type your answer with a space between the fraction and whole number.
Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

battery is the answer

Step-by-step explanation:

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Given that (- 2, 7) is on the graph of f(x) , find the corresponding point for the function f(x + 4).
AveGali [126]

Answer:

\boxed{\ the \ corresponding\  point\  is \ (-6,7)\ }

Step-by-step explanation:

We know that f(-2)=7

x+4 = -2 <=> x = -6

so f(-6+4) = f(-2)=7

then the corresponding point is (-6,7)

3 0
3 years ago
3x + 5x + 8y Simplified
sattari [20]

Answer:

8x + 8y

Step-by-step explanation:

Simplify


Hope this helps. Have a great day. :)

-wfz

7 0
3 years ago
Read 2 more answers
Substitution Method <br> y=x-4<br> y=4x-10
ira [324]

Answer:

x=2 and y= -2

Step-by-step explanation:

Substitute y=x-4 in second equation

x-4=4x-10

get x terms on one side and numbers on other sides

4x-x=10-4

3x=6

divide 3 on both sides

x=2

substitute x=2 in y=x-4

y=2-4

y= -2

4 0
3 years ago
Find the midpoint of the line segment
strojnjashka [21]

Answer:

midpoint (5,4)

Step-by-step explanation:

The midpoint(M) of a segment with endpoints (x₁ , y₁) and ( x₂,  y₂) is

where x₁ = 2 and x₂ = 8

y₁ = 0 and y₂ = 8

M = \frac{x_1 + x_2}{2} ,\frac{y_1 + y_2}{2}

M = \frac{2 + 8}{2} ,\frac{0 + 8}{2}

M = 5 , 4

5 0
3 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
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