1. Percentage
2. Proportion
3. Fraction
4. Rational number (you are correct)
5. LCD (Least common multiple)
The potential roots of the function are, 
And the accurate root is 3 it can be determined by using rules of the rational root equation.
<h2>Given that,</h2>
Function; 
<h3>We have to
determine,</h3>
Which of the values shown are potential roots of the given equation?
<h3>
According to the
question,</h3>
Potential roots of the polynomial are all possible roots of f(x).

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.


The factor of the term 45 are,

And The factor of 3 are,

All the possible roots are,

Now check for all the rational roots which are possible for the given function,

Therefore, x = 3 is the potential root of the given function.
Hence, The potential roots of the function are,
.
For more details about Potential roots refer to the link given below.
brainly.com/question/25873992
Answer:
the answer should be A. The $10 activities total up to $50 and the $20 activities total up to $80 which would total to $130
Step-by-step explanation:
The measure of angle A in the triangle is 18°
<h3>How to determine the measure of angle A?</h3>
The angles in the triangle are given as:
m∠A = (2x − 24)°, m∠B = (x + 8)°, m∠C = (4x + 49)°
The sum of angles in a triangle is 180
So, we have
m∠A + m∠B + m∠C = 180
Substitute the known values in the above equation
So, we have:
2x − 24 + x + 8 + 4x + 49 = 180
Evaluate the like terms
7x = 147
Divide both sides by 7
x = 21
Substitute x = 21 in m∠A = (2x − 24)°
m∠A = (2 * 21 − 24)°
Evaluate
m∠A = 18°
Hence, the measure of angle A in the triangle is 18°
Read more about triangles at:
brainly.com/question/1675117
#SPJ1
<h3><em>Answer:</em></h3><h3><em>B. 0.43</em></h3><h3><em>Step-by-step explanation:</em></h3><h3><em>1. Look at the chart</em></h3><h3><em>2. Then look at the answer I gave u</em></h3><h3><em>3. Use my answer for ur personal use</em></h3><h3><em>4. Thank me</em></h3><h3><em>5. Hope I helped, sorry if not tho</em></h3>