Helpppppo please guyssss

Mathematics

1 answer:

RideAnS [48]3 years ago

8 0

<h3><em>Answer:</em></h3><h3><em>B. 0.43</em></h3><h3><em>Step-by-step explanation:</em></h3><h3><em>1. Look at the chart</em></h3><h3><em>2. Then look at the answer I gave u</em></h3><h3><em>3. Use my answer for ur personal use</em></h3><h3><em>4. Thank me</em></h3><h3><em>5. Hope I helped, sorry if not tho</em></h3>

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If 5/8 of the people in water aerobics class are over age 65 and 1/4 of the people in the class are under age 40,what fraction o

LiRa [457]

I think the answer's 7/8. If you convert 1/4 to 2/8 and add them together, you add 5/8 and 2/8 to get 7/8.

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3 years ago

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Maurinko [17]

There isn’t enough information for us to help you:(

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Read 2 more answers

Value of the expression 6x-2y 5y when x=10 and y=3.

vfiekz [6]

Answer:

-150

Step-by-step explanation:

Multiply & Divide left to right

$60-2*35*3$

Once again Multiply & Divide

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Add & Subtract

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3 years ago

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

<u>Answer-</u>

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$