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3 years ago

P, Q, and R are prime numbers such that 3P + 7Q + 15R = 102. What is Q?

Mathematics

1 answer:

77julia77 [94]3 years ago

8 0

Q is 3

Step-by-step explanation:

The prime numbers are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, ......

They have two factors only 1 and itself
All the them are odd numbers except 2 is an even number
1 is not a prime number because has only one factor

∵ P, Q and R are three prime numbers

∵ 3P + 7Q + 15R = 102

- Factorize 102 into prime numbers

∵ 102 ÷ 2 = 51

∵ 51 ÷ 3 = 17

∴ The prime factorization of 102 is 2 × 3 × 17

∵ 2 , 3 , 17 are prime numbers

- Put them in the equation above to find which one is P and

which is Q and which is R

∵ R has the greatest coefficient, then put R = the smallest prime 2

∵ P has the smallest coefficient, then put P = the greatest prime 17

∴ Q = The last prime 3

- Let us check the value of the left hand side

∵ Left hand side = 3(17) + 7(3) + 15(2) = 51 + 21 + 30 = 102

∵ Right hand side = 102

∴ The prime numbers are P = 17 , Q = 3 , R = 2

Q is 3

Learn more:

You can learn more about the prime numbers in brainly.com/question/4550858

#LearnwithBrainly

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