Let P be the last point in the triangle you have drawn from AB.. It is isosceles and rectangle hence AB^2=2BP^2 hence AP=BP=sqrt(2).
Let Q be the last point in the triangle you have drawn from CD. By the same reasoning, CQ=DQ=sqrt(2)
What is more, AD=AP+PQ+QD=2sqrt(2)+1
5c^3(c^2 + 12c + 36) --> 5c^3(c+6)(c+6) --> 5c^3(c+6)^2
Since two of the triangles are similar that means they are the same thing :
<A = <L
108 = 108
<C is twice from <M so :
<C is 2x < M is x
as you note down the answer you can draw two triangles and label them according to thier values, you will see that triangle ABC has two things now ;
a = 108 and c = 2x
when you have two measures in a triangle you can find the 3rd one :
suppose that third < of triangle ABC is x ;
108 + 2x + x = 180
108 + 3x = 180
3x = 180 - 108
3x = 72
<u> </u><u> x = 24</u><u />
<u> <m = 24 </u>
further if you want to find C :
< c = 2x
< c = 2 ( 24 )
< c = 48
Answer:
.. f (x) = 3x7 – x4 + 2x3 – 5x2 – 4.
Step-by-step explanation: