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WITCHER [35]
3 years ago
10

A 6-foot tall man is standing in front of a school and notices his shadow measures 10 feet. At the same time, he notices the fla

g pole casts a shadow that measures 85 feet. How tall is the flagpole?
A. 51 ft
B. 100 ft
C. 14.7 fr
D. 127 ft
Mathematics
2 answers:
irga5000 [103]3 years ago
4 0

Answer:

The tall of the flag pole is 51 ft answer (A)

Step-by-step explanation:

∵ The tall of the man = 6 ft

∵ The his shadow = 10 ft

∵ The shadow of the flag pole = 85 ft

∵ Tall of the man/tall of the flag = shadow of the man/shadow

   of the flag

∴ 6/x = 10/85 ⇒ where x is the tall of the flag

∴ x = (6 × 85) ÷ 10 = 510 ÷ 10 = 51 ft

∴ The tall of the flag pole is 51 ft

MaRussiya [10]3 years ago
4 0

The answer is A. The flagpole is 51feet.

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P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots

The probability of the arrival of three or fewer passengers in one minute is calculated by substituting \lambda = 10λ=10 and x = 0,1,2,3x=0,1,2,3 in the formula as,

\begin{array}{c}\\P\left( {X \le 3} \right) = \sum\limits_{x = 0}^3 {\frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}}} \\\\ = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^1}}}{{1!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^2}}}{{2!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^3}}}{{3!}}\\\\ = 0.000045 + 0.00045 + 0.00227 + 0.00756\\\\ = 0.0103\\\end{array}

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Part c:

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​

​

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