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Bond [772]
3 years ago
6

a carp can travel at a speed of 3 and 7/10 miles per hour. at this rate how far can a carp travel in 2 and 1/2 hours

Mathematics
2 answers:
Basile [38]3 years ago
8 0
I believe the answer is the carp travels 9 1/<span>4</span> miles in 2 <span>1/2</span><span> hours</span>
allsm [11]3 years ago
6 0
Answer:
number of miles = 9.25 miles = 9 and 1/4 miles

Explanation:
For simplicity, I will convert the mixed numbers into decimals to ease the calculations. Then I will convert the final answer back into a mixed number.
So,
3 and 7/10 miles = 3.7 miles
2 and 1/2 hours = 2.5 hours

Now, we are given that the rate of the car is 3.7 miles per hour. To know the time taken by the car to travel 2.5 miles, we will simply do cross multiplication as follows:
3.7 miles ................> 1 hour
?? miles ................> 2.5 hous
number of miles = (2.5*3.7) / 1 = 9.25 miles

Now, converting this back into mixed number, we will find that:
number of miles = 9.25 miles = 9 and 1/4 miles

Hope this helps :)
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So,

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"six feet less than the width (w)"

w - 6
4 0
3 years ago
Someone please help me !!!! Will mark Brianliest !!!!!!!!!!!!!!!!
BARSIC [14]

Answer:

once again try -4+1

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5 0
3 years ago
True or False? true-false: Please select true or false and click "submit."
iragen [17]
Im positive its false because they dont add up

5 0
3 years ago
Read 2 more answers
16.
ss7ja [257]

The simplified polynomial that represents how many more economy cars are rented in w weeks than full-size cars is 53 - w.

<h3>Linear equation:</h3>

Linear equation is an equation in which the highest power of the variable is equals to one.

Therefore, the number of economy-size cars rented in w weeks is represented as follows:

  • 152 + 3w

The number of full-size cars rented in w weeks is represented as follows:

  • 99 + 2w

where

w = number of weeks

A  simplified polynomial that represents how many more economy cars are rented in w weeks than full-size cars is as follows:

  • 152 + 3w - (99 + 2w)
  • 152 + 3w - 99 - 2w
  • 53 - w

learn more on polynomial here: brainly.com/question/2566362

5 0
2 years ago
For 100​ births, P(exactly ​girls) and ​P( or more ​girls). Is girls in 100 births a significantly high number of​ girls? Which
madreJ [45]

Answer;

The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05

Step-by-step explanation:

The complete question is as follows;

For 100 births, P(exactly 56 girls = 0.0390 and P 56 or more girls = 0.136. Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less V so 56 girls in 100 birthsa significantly high number of girls because the relevant probability is The relevant probability is 0.05

Solution is as follows;

Here. we want to know which of the probabilities is relevant to answering the question and also if 56 out of a total of 100 is sufficient enough to provide answer to the question.

Now, to answer this question, it would be best to reach a conclusion or let’s say draw a conclusion from the given information.

The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05

7 0
3 years ago
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