All categories

3 years ago

(3x-60)+120=180 pls help me

Mathematics

2 answers:

Olegator [25]3 years ago

7 0

Answer:

x = 40

Step-by-step explanation:

3x - 60 + 120 = 180

3x + 60 = 180

3x = 180 - 60

3x = 120

x = 120/3

x = 40

Hoping it helps you dear

Rashid [163]3 years ago

6 0

Answer:

x=40

Step-by-step explanation:

Subtract 120 from each side to get 3x-60=60

Add 60 to each side to get 3x=120

Divide by 3 on each side to get x=40

You might be interested in

Precalculus PLEASE HELP Math

Blababa [14]

Answer:

Step-by-step explanation:

tan 17=h/18

h=18 tan 17

tan 38=(h+x)/18

h+x=18 tan 38

h+x-h=18 tan 38-18 tan 17

x=18(tan 38-tan 17)≈8.56

7 0

3 years ago

a flagpole casts a shadow 160 feet long. At the same time, a boy standing nearby who is 5 feet tall casts a shadow 20 feet long.

Veronika [31]

Answer:

The flagpole is 40 feet tall.

Step-by-step explanation:

So, we are looking for the height of the flagpole. Let h represent this height.

Boy - 5 feet in height and casts a 20-foot shadow

Flag pole - h feet in height and casts a 160-foot shadow

The relationship looks something like this:

5 : 20 :: h : 160

$\frac{5}{20} =\frac{h}{160}$

Now, we can cross multiply to find h!

$20h=800\\h=40$

So, the flagpole is 40 feet tall

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Have a nice day, fam. Spread The Love!

3 0

3 years ago

Read 2 more answers

Write an expression for the area of the shaded region in its simplest form. Show all of your steps.

patriot [66]

The area of the shaded region will be the area of the rectangle minus the area of the white square inside of it:

((x+10)(2x+5)) - ((x+1)(x+1))

First, FOIL both of the areas separately:

(2x^2 + 5x + 20x + 50) - (x^2 + x + x + 1)

Simplify within the parentheses by adding like terms:

(2x^2 + 25x + 50) - (x^2 + 2x + 1)

Now, subtract one equation from the other:

2x^2 + 25x + 50
-x^2 - 2x - 1
= x^2 + 23x + 49

This will be the equation for the area.

3 0

3 years ago

How many bits does 2 to the 100 have if written in base 2?

S_A_V [24]

Not sure how to give a hint without blatantly giving the answer but...

Consider an n - digit number in base b.

That is N=an−1an−2.....a0=∑k=0akbk
N
=
a
n
−
1
a
n
−
2
.
.
.
.
.
a
0
=
∑
k
=
0
a
k
b
k
Note aka
k
<
b
so we can easily show NN
<
b
n
(may have to repeat and argue inductively.

And presumably to be n - digit than an−1≠0
a
n
−
1
≠
0
so N≥bn−1
N
≥
b
n
−
1
.

So we have: every n digit number is between bn−1
b
n
−
1
inclusively and bn
b
n
exclusively. This should be blindingly obvious to us if b=10
b
=
10
.

So... that's a really important and fundamental result. Remember and use it.

4 0

3 years ago

And this (4+i)(4-i) show work so i can understand pls ;-;

Irina18 [472]