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kompoz [17]
4 years ago
5

I'd really appreciate it if anyone could help! :) I'll give Brainliest!

Mathematics
1 answer:
Dmitrij [34]4 years ago
8 0

B and C are correct!

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A rectangular trough, 2.0 m long, 0.70 m wide, and 0.45 m deep, is completely full of water. one end of the trough has a small d
BaLLatris [955]
Given that <span>a rectangular trough, 2.0 m long, 0.70 m wide, and 0.45 m deep, completely full of water is connected to </span>a small drain plug right at the bottom edge

If the plug is pulled, the <span>speed at which water emerges from the hole is given by</span>

V=\sqrt{2gh} \\  \\ =\sqrt{2\times9.8\times0.45} \\  \\ =\sqrt{8.82}=3.0m/s
8 0
3 years ago
Which step should be used to prove that point P is equidistant from R and Q?
mariarad [96]
Equidistance means
Distance from R to P equals
Distance from Q to P.

So, in mathematical form,
PR = PQ
5 0
4 years ago
Help ASAP for this question All of the following are equivalent except<br> 0.6 0.06 6% 3/50
stich3 [128]

Answer:

0.6

Step-by-step explanation:

0.6 0.06 6% 3/50 are equivalent to

0.6 0.06 6% 6/100.  0.6 is 10 times larger than the other three.

Thus, 0.06 6% 3/50 are equivalent, and 0.6 does not belong to the group.

5 0
3 years ago
The equations of two lines are:
Anit [1.1K]

Answer:

x = 3

Step-by-step explanation:

2x - y = 4

y = -2x + 8

-y = -2x + 4

y = -2x + 8

0 = -4x + 12

-4x = -12

x = 3

4 0
3 years ago
The expression can be simplified and written without negative exponents as...
Ksju [112]

\dfrac{(27y^{-2})^\frac{1}{3}}{y^{-\frac{2}{3}}}=(27)^\frac{1}{3}(y^{-2})^\frac{1}{3}:\dfrac{1}{y^\frac{2}{3}}=\sqrt[3]{27}y^{-2\cdot\frac{1}{3}}\cdot y^\frac{2}{3}\\\\=3y^{-\frac{2}{3}}\cdot y^\frac{2}{3}=3y^{-\frac{2}{3}+\frac{2}{3}}=3y^0=3\\\\\text{used:}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\a^\frac{1}{n}=\sqrt[n]{a}\\\\a^{-n}=\dfrac{1}{a^n}\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^0=1,\ a\neq0

6 0
4 years ago
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