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solong [7]
3 years ago
5

A taxi charges a flat rate of $3.00 plus $1.50 per mile. If Xander has $45.00, what inequality represents m, the distances in mi

les he can travel in the taxi?
Mathematics
2 answers:
dalvyx [7]3 years ago
6 0

Answer:

1 1/5

Step-by-step explanation:

48/40 = 1 8/40

1 8/40 Simplify to 1 1/5

Hope this helps!

PolarNik [594]3 years ago
3 0

Answer:

D. <em>m</em>≤28

Step-by-step explanation:

Just trust me my friendings

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kiruha [24]
First, you have to find the LCD. The LCD of 4 and 7 is 28, so you rewrite the fraction:
7/28
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Then you add them.
8 0
3 years ago
Read 2 more answers
Use scientific notation to determine the answer :
vampirchik [111]
A= 1.5 × 10^10




Hope that helps
3 0
3 years ago
Isaac keeps track of the amount of money in his savings certificate each month. He has accumulated the following data:
Dafna1 [17]

Answer:

d. The common ratio is 1.1

Step-by-step explanation:

To see if the data has a common ratio or common difference, we have to see if the division between them is equal(common ratio), or if the difference between them is equal(common difference).

In this case, since 60.5 - 55 \neq 55 - 50, it has a common ratio.

To find it, we divide consecutive terms. For example:

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So the correct answer is:

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3 0
2 years ago
Find the measure of the indicated angle. Round to the nearest degree.
slava [35]

Answer:

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

5)

Adj = 14

Hyp = 26

∠X

so use

CAH

Cos(X) = 14/26

X = arcCos(14/26)

X = 57.421°

X = 57.4 ° ( rounded to nearest 10th )

6)

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use SOH

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7)

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Adj = 29

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use TOA

Tan(x) = 29 / 24

X = arcTan( 29 /24)

X = 50.389

X = 50.4 °  ( rounded to nearest 10th )

8)

∠X

Adj = 22

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use TOA agian

Tan(x) = 6 / 22

X = arcTan(6/22)

X = 5.194

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:)

8 0
3 years ago
In the equation below, what is the coefficient of the variable?
qaws [65]
B

but i have to write more to let me post this so here it is




7 0
3 years ago
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