Answer:
can you label each part of the book. coppy and write your
<span>2/3 (x-7)= -2
x - 7 = -2 * 3/2
x - 7 = -3
x = -3 + 7
x = 4</span>

Step 1:
Here we have -3 in subtraction on the left side, so when we take it to the right we apply opposite operation of subtraction that is addition.


Step 2:
Next we have 4 in multiplication on left side, so dividing right side by 4,


Step 3:
taking log on both sides


Step 4:
Dividing right side by 2,
x= ln (3.75) /2 = 0.66088
Answer : x = 0.66088..
Answer:
the answer is 50
Step-by-step explanation:
first you plug in the x and y in the equation, making it 6(7)=-4(-2) then, you multiply the numbers together, making the equation 42+8. finally, you add those numbers together, giving you the answer 50
Answer:
$
Step-by-step explanation:
÷
= 

Hope this helps