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Leviafan [203]
3 years ago
13

Please please help me out!!!!!!!!!

Mathematics
2 answers:
anyanavicka [17]3 years ago
8 0

Answer:

y = \frac{3}{4} x + \frac{1}{4}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 3, - 2) and (x₂, y₂ ) = (5, 4) ← 2 points on the line

m = \frac{4+2}{5+3} = \frac{6}{8} = \frac{3}{4}, thus

y = \frac{3}{4} x + c ← is the partial equation of the line

To find c substitute either of the 2 points into the partial equation

Using (5, 4), then

4 = \frac{15}{4} + c ⇒ c = 4 - \frac{15}{4} = \frac{1}{4}

y = \frac{3}{4} x + \frac{1}{4} ← equation of line

Black_prince [1.1K]3 years ago
3 0

Answer:

y = 3/4x + 1/4.

Step-by-step explanation:

The upper dot on the line is the point (5, 4) and the lower one is the point (-3,-2) so the slope of the line is:

(4 - -2) / (5 - -3)

= 6/8

= 3/4.

Using the point slope form of a line with m = 3/4 and (x1,y1) = (5,4)

y - y1 = m(x - x1)

y - 4 = 3/4(x - 5)

y = 3/4x + 1/4

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Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

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Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

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The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

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The sample size was of 16.

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We can figure out how many he has saved up already by multiplying the number of weeks (12) by how much he saved each week ($8) which equals $96. Now we have to subtract $96 from $250 which equals $154. Now we need divide this amount by the remaining weeks until he wants to purchase his bike (7), so 154/7 which equals $22.

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