All categories

3 years ago

AM I CORRECT FOR 10? (please ONLY CORRECT ANSWER lots of points!!)

Mathematics

2 answers:

11111nata11111 [884]3 years ago

4 0

No you got the wrong answer the answer is 256 pi.

lara [203]3 years ago

4 0

no your are incorrect for 10 if you use the formula

WORKING:

A=\pi r ^2

A= 3.14 * 16^2

A= 3.14* 256

A = 256 \pi

You might be interested in

What is the solution to the inequality <br> 7x+2<-3x+1

Allisa [31]

Answer:

4x+3

Step-by-step explanation:

4 0

3 years ago

What is the square root of nine

antoniya [11.8K]

The square root of nine is 3.

8 0

3 years ago

Read 2 more answers

Michael's team is trying to determine how they can process shipments more quickly. He has convened a large group to come up with

xenn [34]

Step-by-step explanation:

d is correct answer as i think.

4 0

3 years ago

PLEASE HELP PLEASE HURRY!!!!!!!!!<br> BRAINLIEST AVAILABLE

zalisa [80]

Rule for 1 is the rule for 1 is 14 times 3.5^x and it is exponential

The second one is is also exponential and the rule is 32 times .25^x and the last one is is linear and the rule is 5x+-4

3 0

4 years ago

Read 2 more answers

A man has 32 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 545 cents, how many d

inn [45]

A dime is worth 10 cents and a quarter is worth 25 cents.

Let D be the number of dimes and Q be the number of quarters.

Since the total amount of coins in the pocket is 32, then:

$D+Q=32$

On the other hand, the total value of D dimes is 10D, while the total value of Q dimes is 25Q. Then, the total value of D dimes and Q cuarters is 10D+25Q, which must be equal to 545. Then:

$10D+25Q=545$

Notice that we have found a 2x2 system of equations:

$\begin{gathered} D+Q=32 \\ 10D+25Q=545 \end{gathered}$

Solve the system using the substitution method. To do so, isolate D from the first equation and replace the expression for D into the second equation to obtain a single equation in terms of Q:

$\begin{gathered} D+Q=32 \\ \Rightarrow D=32-Q \\ \\ 10D+25Q=545 \\ \Rightarrow10(32-Q)+25Q=545 \\ \Rightarrow320-10Q+25Q=545 \\ \Rightarrow25Q-10Q=545-320 \\ \Rightarrow15Q=225 \\ \Rightarrow Q=\frac{225}{15} \\ \\ \therefore Q=15 \end{gathered}$

Replace back Q=15 into the expression for D to find the amount of dimes:

$\begin{gathered} D=32-Q \\ =32-15 \\ =17 \end{gathered}$

Therefore, the amount of dimes that the man has is 17.

7 0

1 year ago