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3 years ago

Which equation has a constant of proportionality equal to

Mathematics

1 answer:

seraphim [82]3 years ago

5 0

There are many equations that has a constant of

proportionality, might want to make it more specific.

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A hot air balloon holds 1,592 cubic meters of helium. The density of helium is 0.1785 kilograms per cubic

yuradex [85]

Answer: 285.2 kg

Step-by-step explanation:

Given

The volume of helium in the balloon is $V=1592\ m^3$

The density of the helium is $\rho =0.1785\ kg/m^3$

Mass of the helium gas is given by the product of density and volume

$\Rightarrow M=\rho \cdot V\\\Rightarrow M=0.1785\times 1592\\\Rightarrow M=285.2\ kg$

Thus, the mass of gas is 285.2 kg

3 0

3 years ago

HUNTER filed for Chapter 13 bankruptcy in 2009. Even if she planned to take the maximum time allowed under Chapter 13 to repay h

Ilya [14]

She must have planned No later than 2014

7 0

3 years ago

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Find the product: −5/3 (−2/3 )(−18)

Dovator [93]

Answer:

A) −20

Step-by-step explanation:

−5/3 (−2/3 )(−18)

Multiply the first and second terms. A negative times a negative is a positive

-5/3 * -2/3 = 10/9

10/9 * -18

Rewriting for easier math

-18/9 * 10

-2 * 10

-20

4 0

3 years ago

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I want to fence in a square vegetable patch. The fencing for the east and west sides costs $8 per foot, and the fencing for th

brilliants [131]

16X plus 10X equals answer

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3 years ago

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Find the absolute extreme of the function on the closed interval. y=9e^xsinx , [0,pi]

Molodets [167]

For convenience sake, I will let $y=f(x)=9e^{x}\sin x$

First, we evaluate the function at the endpoints of the interval.

$f(0)=9e^{0}\sin(0)=0\\\\f(\pi)=9e^{\pi}\sin(\pi)=0$

Then, we need to find the critical points.

We can start by taking the derivative using the power rule.

$f'(x)=9e^{x} \frac{d}{dx} \sin x+9\sin x \frac{d}{dx} e^{x}=9e^{x}(\cos x+\sin x)$

Setting this equal to 0,

$9e^x (\cos x+\sin x)=0$

Since $9e^x > 0$ , we can divide both sides by $9e^x$ .

$\cos x+\sin x=0\\\\\sin x=-\cos x\\\\\tan x=-1\\\\x=\frac{3\pi}{4}$

$f\left(\frac{3\pi}{4} \right)=9e^{3\pi/4}\sin \left(\frac{3\pi}{4} \right)=\frac{9\sqrt{2}e^{3\pi/4}}{2}$

So, the absolute minimum is $\boxed{\left(\frac{3\pi}{4}, \frac{9\sqrt{2}e^{3\pi/4}}{\sqrt{2}} \right)}$ and the absolute minima are $\boxed{(0,0), (\pi, 0)}$

3 0

2 years ago