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2 years ago

Which equation has a constant of proportionality equal to

Mathematics

1 answer:

seraphim [82]2 years ago

5 0

There are many equations that has a constant of

proportionality, might want to make it more specific.

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What is the midpoint of (-7,-9) (6,3)

Advocard [28]

Answer :

Let the first term of both the terms be $\: \sf \: x _1 \: \: \& \: \: x _2$ and last term be $\: \sf \: y _1 \: \: \& \: \: y_2\\$

Now, by using the mid point formula to find the mid point of the segment -

$\\ \sf \bigg( \frac{x_1 + x_2}{2} , \: \frac{y_1 + y_2}{2} \bigg) \\$

Now, by substituting the values of both x and y -

$\\ \sf \bigg( \frac{ - 7 + 6}{2} , \: \frac{ - 9 + 3}{2} \bigg) \\$

Adding -7 and 6 -

$\\ \sf \bigg( \frac{ - 1}{2} , \frac{ - 9 + 3}{2} \bigg) \\$

Now, move the negative in front of the fraction -

$\\ \sf \bigg( \frac{ - 1}{2} , \frac{ - 6}{2} \bigg) \\ \\ \\ \sf \bigg( \frac{ - 1}{2} , - 3\bigg) \\$

6 0

3 years ago

Answer of a ²-10a+16-6b-b^2

german

$\quad a^2-10a+16-6b-b^2$

$=(a^2-10a)-(b^2+6b) +16$

$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$

$=(a-5)^2-25-(b+3)^2+9+16$

$=(a-5)^2-(b+3)^2$

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3 years ago

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amid [387]

Answer:

the variance is 6.6

sry for not showing work

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