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3 years ago

Please help!! Explain how you got the answer!

Mathematics

1 answer:

mash [69]3 years ago

8 0

multiply 3.5 x 3 = 10.5

add -5 +-10 = -15

so you have 10.5 x 10^15

then you need to move the decimal point 1 place to the left to get 1.05

since you move the decimal point 1 place to the left you add 1 to the -15 to get -14

so answer = 1.05 x 10^-14

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A jar at the fishing shop holds 72 worms. A cup holds 8 worms. How many times

Anettt [7]

Answer:

9 times. 72/8=t or 72=8t.

Explanation:

I'm afraid the answer choices are slightly mixed up, but acceptable answers would probably include 72/8=t or 72=8t. Simply put the two numbers into a fraction (72/8) to get how many times larger or smaller the thing is. In this case, it would be 9 times as many worms.

5 0

3 years ago

Read 2 more answers

The solution shown for the equation is incorrect. What is the correct solution? What is the error?

Degger [83]

-9(3-r)=45
-27+9t=45
9r=45+27
R=72/9
R=8
The answer is 8 not -8

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2 years ago

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4 0

2 years ago

A certain company's main source of income is a mobile app. The company's annual profit (in millions of dollars) as a function of

liberstina [14]

Answer:

x = $3, or x = $11

Step-by-step explanation:

The equation given is $P(x)=-2(x-3)(x-11)$

where

P(x) is the profit, and
x is the app price

<u>We want app prices (x's) when profit (P(x)) is 0, so plugging in into the equation:</u>

$P(x)=-2(x-3)(x-11)\\0=-2(x-3)(x-11)\\0=(x-3)(x-11)$

<em>It means (x-3) = 0 OR (x-11) = 0</em>

So, x = 3, or 11

7 0

2 years ago

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Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.

avanturin [10]

In spherical coordinates, we have

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}$

which gives volume element

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

and so the triple integral is given by

$\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$
$=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi$
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4 0

3 years ago