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Vedmedyk [2.9K]
2 years ago
9

NEED HELP ASAP PLEASE WILL GIVE BRAINLIEST:

Mathematics
1 answer:
ivann1987 [24]2 years ago
4 0

Answer:

It can go 250 m deep

Step-by-step explanation:

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Write the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 in this order and insert ‘+ ‘or ‘–' between them to get the result (a) 5 (b) –3
Liula [17]

Answer:

5

Step-by-step explanation:

we can write the digits in following form

0+1-2+3-4+5-6+7-8+9

= -1 - 1 -1 -1 +9

=-2-2+9

= -4+9

= 5

7 0
3 years ago
Find the measure of c
Volgvan

9514 1404 393

Answer:

  140°

Step-by-step explanation:

The long arc intercepted by angle c is 360° -80° = 280°. The measure of inscribed angle c is half the measure of the arc it intercepts.

  c = 280°/2 = 140°

5 0
3 years ago
Is X +3 a factor of 2X squared minus 2X -12
Fantom [35]

Answer: No, x+3 is not a factor of 2x^2-2x-12

========================================================

Explanation:

Let p(x) = 2x^2 - 2x - 12

If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).

Compare x+3 = x-(-3) to x-k to find that k = -3.

Plug x = -3 into the function

p(x) = 2x^2 - 2x - 12

p(-3) = 2(-3)^2 - 2(-3) - 12

p(-3) = 12

We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12

----------------------------------------

Let's see what happens when we factor p(x)

2x^2 - 2x - 12

2(x^2 - x - 6)

2(x - 3)(x + 2)

The factors here are 2, x-3 and x+2

3 0
3 years ago
Find the area of quadrilateral with vertices at points (3,0)(4,5)(-1,4)(-2,-1)
guapka [62]

Answer: 20

Step-by-step explanation:

Let 's complete our quadrilateral to a rectangle ; and subtract from it the area highlighted in red

\displaystyle \rm S_{\diamond}=6\cdot 5 =30 \\\\ S_{ABCD}=30-(5:2+5:2+5:2+3:2+1\cdot1)=30-(7,5+1,5+1)=\\\\30-10=20 \\\\ S_{ABCD}=20

4 0
3 years ago
Read 2 more answers
After sailing 12 mi, a sailor changed direction and increased the boat's speed by 4 mph. an additional 18 mi was sailed at the i
inessss [21]
Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed 
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
8 0
3 years ago
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