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Masteriza [31]
2 years ago
10

Please help will mark BRAINLIEST

Mathematics
1 answer:
ddd [48]2 years ago
6 0

Answer:

Yes they are congruent

Step-by-step explanation:

they are congruent because they have 2 similar side lengths and 1 equal angle

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HURRY PLEASE!! How many sides are there in a regular polygon which has 120 degrees in each of its angeles?
N76 [4]
Number of angles = number of sides

180 - 120 = 60 (calculating the exterior angle)

360 / 60 = 6

There are 6 sides.

Hope this helps! :)
7 0
2 years ago
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What property does the number sentence show? 8+0=8
zubka84 [21]
Identity Property of Zero!
I hope this helps xD
7 0
3 years ago
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What is the quotient of (x cubed 3 x squared minus 4 x minus 12) divided by (x squared 5 x 6)?
liubo4ka [24]

The quotient of x^{3}+3x^{2} -4x-12 divided by x^{2} +5x+6 is (x-2_.

Given the polynomial x^{3}+3x^{2} -4x-12 and x^{2} +5x+6 and the first expression or polynomial is divided by second.

Quotient is a number that is obtained by dividing two numbers. It can be of two numbers or two expressions. Remainder is a number or an expression left after division of two numbers.

To find the quotient of x^{3}+3x^{2} -4x-12 divided by  , we have to divide the expression first.

We know that ,

Divident=Divisor*Quotient+remainder

x^{3}+3x^{2} -4x-12=x^{2} +5x-6*(x-2)-12

If we carefully watch the above equation and compares with the above formula then we can easily find that the value of quotient is (x-2).

Hence the quotient of x^{3}+3x^{2} -4x-12 divided by x^{2} +5x-6 is (x-2).

Learnmore about quotient at brainly.com/question/673545

#SPJ4

Question is incomplete as the given expressions are incomplete as they should be like this:

x^{3}+3x^{2} -4x-12 and x^{2} +5x-6.

4 0
1 year ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
2 years ago
Help with this answer please?
puteri [66]
It would be Adjacent/hypotenus which is 36/39 and when simplified the answer is 12/13
3 0
3 years ago
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