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docker41 [41]
4 years ago
7

Someone help ASAP solve -5x^2+7x=-9

Mathematics
1 answer:
Ray Of Light [21]4 years ago
5 0

Answer:

x=\frac{7 +/-\sqrt{229} }{10}

Step-by-step explanation:

To solve the quadratic, use inverse operations to set it equal to 0.

-5x^2+7x=-9\\-5x^2+7x+9=0

To solve, use the quadratic formula and substitute a= -5, b= 7 and c= 9.

x=\frac{-b +/-\sqrt{b^2-4ac} }{2a} \\\\x=\frac{-7 +/-\sqrt{7^2-4(-5)(9)} }{2(-5)} \\\\x=\frac{-7 +/-\sqrt{49+180} }{-10} \\\\x=\frac{7 +/-\sqrt{229} }{10}

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Lady bird [3.3K]

Answer:

Q(-10) = 299

Step-by-step explanation:

Q(x) = 3x^{2} - 1Q(-10) = 3(-10)^{2} - 1

Q(-10) = 3(100) - 1  (-10 to the second power is 100 (negative times a negative equals a positive)

Q(-10) = 300 - 1  3 times 100 equal 300

Q(-10) = 299

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