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Hunter-Best [27]
3 years ago
14

Compute 5e2 - 4g + 7 where e = 4 and g = 6 ?

Mathematics
1 answer:
Elza [17]3 years ago
3 0

The value of expression is 63 when e = 4 and g = 6

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

5e^2-4g+7

We have to solve the expression

Given that e = 4 and g = 6

<em><u>Substitute e = 4 and g = 6 in given expression</u></em>

\rightarrow 5(4)^2 -4(6) + 7\\\\Simplify\ the\ above\ equation\\\\\rightarrow 5(16) -24 + 7\\\\\rightarrow 80-24+7\\\\Simplify\\\\\rightarrow 56+7=63

Thus value of expression is 63

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Mr. Jones has three tables in his classroom. Each table has four
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Answer:

24

Step-by-step explanation:

you would multiply 3 tables by 4 students, that would be twelve. then 12 times 2, which is 24. Or you could find the pencils by multiplying 2 with 8 and then multiplying by 3. :)

5 0
3 years ago
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earnstyle [38]

Answer:

She should order a total of 5,160 medium sized t-shirts

Step-by-step explanation:

To calculate the number of medium sized t-shirt to be ordered, we shall be using the proportion of students that wanted medium sized t-shirt in her survey to multiply the total number of students that we have.

From the question, we can identify that the probability that a student will like a medium sized t-shirt is simply 129/300

Now we have about 12000 students in the University, using the probability from the survey, the number of medium sized t shirt she should order would be;

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8 0
3 years ago
The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.
zzz [600]
Hello,

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6 0
4 years ago
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Answer:

40th and 80th visit

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Step-by-step explanation:

personally, I believe that the simplest way to solve this is use an excel spreadsheet to see which visits would include both a free beverage and a free appetizer:

  • both rewards would happen only twice, at the 40th and 80th visit.

you can also calculate it mathematically since multiples of 8 and 10 do not repeat themselves very much, only when 8 is multiplied by 5 and 10.

4 0
3 years ago
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amid [387]
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8 0
3 years ago
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