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3 years ago

Compute 5e2 - 4g + 7 where e = 4 and g = 6 ?

Mathematics

1 answer:

Elza [17]3 years ago

3 0

The value of expression is 63 when e = 4 and g = 6

Solution:

Given expression is:

$5e^2-4g+7$

We have to solve the expression

Given that e = 4 and g = 6

Substitute e = 4 and g = 6 in given expression

$\rightarrow 5(4)^2 -4(6) + 7\\\\Simplify\ the\ above\ equation\\\\\rightarrow 5(16) -24 + 7\\\\\rightarrow 80-24+7\\\\Simplify\\\\\rightarrow 56+7=63$

Thus value of expression is 63

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Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

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4 years ago

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Citrus2011 [14]

They are corresponding angles

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3 years ago

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There are 1,620 minutes of music to be put on 9 CD's. If the same number of minutes fits on each CD, how many minutes of music f

irakobra [83]

Answer:

180 minutes

Step-by-step explanation:

take 1,620 divide it by 9 and there is your answer

hope this helped

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3 years ago

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What is the equation of the quadratic graph with a focus of (3, −1) and a directrix of y = 1?

Tomtit [17]

Use our brains and what we know
f(x)=a(x-h)²+k
vetex is (h,k)
and a is te leading coefient

if directix is below the focus, then it opens up and a is positive
if directix is above focus, then it opens down and a is negaitve

vertex is in between directix and focus

so
(3,-1) and y=1
-1<1
so directix is above
a is negative

directly in between
distance from -1 to 1 is 2
2/2=1

1 above (3,-1) is (3,0)
vertex is (3,0)

y=a(x-3)²+0
y=a(x-3)²

the only option with a negative 'a' value is B

answer is B

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3 years ago

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Kahleela starts the engine on her small private airplane. The engine drives a propeller with a radius of 8.5 feet and its center

algol13

Answer:

a=21.1

Step-by-step explanation:

You can use the given (incorrect) equation and fill in the value of t to find h:

h = 12.5 +9sin(750(3.5)) = 3.68 . . . . feet

Or, you can use the correct equation, or just your knowledge of revolutions:

h = 12.5 +9sin(750(2π·3.5)) = 12.5 . . . . feet

in 3.5 minutes at 750 revolutions per minute, the propeller makes 2625 full revolutions, so is back where it started — at 12.5 feet above the ground.

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